Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 03 May 2015, 05:05

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Set S consists of five consectuve integers, and set T

Author Message
TAGS:
Current Student
Joined: 31 Aug 2007
Posts: 371
Followers: 1

Kudos [?]: 53 [0], given: 1

Set S consists of five consectuve integers, and set T [#permalink]  17 Apr 2008, 16:43
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
Set S consists of five consectuve integers, and set T consists of seven consecutive integers. Is the median of the numbers in set S equal to the median of the numbers in set T?

C1. The median of the numbers in set S is 0.

C2. The sum of the numbers in set S is equal to the sum of the numbers in set T.
Director
Joined: 10 Sep 2007
Posts: 949
Followers: 7

Kudos [?]: 205 [1] , given: 0

Re: DS median of sets [#permalink]  17 Apr 2008, 18:20
1
KUDOS
Given set S = {a-2d,a-d,a,a+d,a+2d}, where d = 1, and a is any integer.
So median of set S = a, and Average = 5a/5 = a

Given set T = {b-3d,b-2d,b-d,b,b+d,b+2d,b+3d}, where d = 1, and b is any integer.
So median of set T = b, and Average = 7b/7 = b

Statement 1:
Tells us median of set S = 0 => a = 0, But this statement tells us nothing about T, so insufficient.

Statement 2:
Tells us 5a = 7b => a = 7b/5, which means a (median of set S) is not equal to b(median of set T) provided b is not equal to 0, otherwise a will become 0, so this statement alone is not sufficient.

Combining both statements:
From statement one we know a=0, so statement two tells us b is also zero. So both sets have same median.

SVP
Joined: 04 May 2006
Posts: 1936
Schools: CBS, Kellogg
Followers: 19

Kudos [?]: 440 [0], given: 1

Re: DS median of sets [#permalink]  17 Apr 2008, 19:34
abhijit_sen wrote:
Given set S = {a-2d,a-d,a,a+d,a+2d}, where d = 1, and a is any integer.
So median of set S = a, and Average = 5a/5 = a

Given set T = {b-3d,b-2d,b-d,b,b+d,b+2d,b+3d}, where d = 1, and b is any integer.
So median of set T = b, and Average = 7b/7 = b

Statement 1:
Tells us median of set S = 0 => a = 0, But this statement tells us nothing about T, so insufficient.

Statement 2:
Tells us 5a = 7b => a = 7b/5, which means a (median of set S) is not equal to b(median of set T) provided b is not equal to 0, otherwise a will become 0, so this statement alone is not sufficient.

Combining both statements:
From statement one we know a=0, so statement two tells us b is also zero. So both sets have same median.

_________________
Senior Manager
Joined: 29 Jan 2007
Posts: 450
Location: Earth
Followers: 2

Kudos [?]: 40 [0], given: 0

Re: DS median of sets [#permalink]  18 Apr 2008, 22:57
abhijit_sen wrote:
Given set S = {a-2d,a-d,a,a+d,a+2d}, where d = 1, and a is any integer.
So median of set S = a, and Average = 5a/5 = a

Given set T = {b-3d,b-2d,b-d,b,b+d,b+2d,b+3d}, where d = 1, and b is any integer.
So median of set T = b, and Average = 7b/7 = b

Statement 1:
Tells us median of set S = 0 => a = 0, But this statement tells us nothing about T, so insufficient.

Statement 2:
Tells us 5a = 7b => a = 7b/5, which means a (median of set S) is not equal to b(median of set T) provided b is not equal to 0, otherwise a will become 0, so this statement alone is not sufficient.

Combining both statements:
From statement one we know a=0, so statement two tells us b is also zero. So both sets have same median.

Abhijit,
My hunch is, Answer could be B here

I think , for 2 sets of "consecutive" number, 5a=7b is possible only when a=b=0
Which makes B SUFFICIENT.

Can you think of example where B is not sufficient ?
CEO
Joined: 17 Nov 2007
Posts: 3578
Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40
Followers: 406

Kudos [?]: 2140 [0], given: 359

Re: DS median of sets [#permalink]  18 Apr 2008, 23:39
Expert's post
kyatin wrote:
Abhijit,
My hunch is, Answer could be B here

I think , for 2 sets of "consecutive" number, 5a=7b is possible only when a=b=0
Which makes B SUFFICIENT.

Can you think of example where B is not sufficient ?

s={5,6,7,8,9} t={2,3,4,5,6,7,8} sum=35 but medians are different.
_________________

HOT! GMAT TOOLKIT 2 (iOS) / GMAT TOOLKIT (Android) - The OFFICIAL GMAT CLUB PREP APP, a must-have app especially if you aim at 700+ | PrepGame

Senior Manager
Joined: 29 Jan 2007
Posts: 450
Location: Earth
Followers: 2

Kudos [?]: 40 [0], given: 0

Re: DS median of sets [#permalink]  19 Apr 2008, 07:11
walker wrote:
kyatin wrote:
Abhijit,
My hunch is, Answer could be B here

I think , for 2 sets of "consecutive" number, 5a=7b is possible only when a=b=0
Which makes B SUFFICIENT.

Can you think of example where B is not sufficient ?

s={5,6,7,8,9} t={2,3,4,5,6,7,8} sum=35 but medians are different.

heheh. that was easy.

I did use his equation to just plug in numbers...but created two sequences by incorrect calculations..

Re: DS median of sets   [#permalink] 19 Apr 2008, 07:11
Similar topics Replies Last post
Similar
Topics:
13 Set S consists of five consecutive integers, and set T consi 10 19 Feb 2011, 09:43
Set S consists of five consecutive integers, and set T 4 18 Jun 2008, 17:54
Set S consists of 5 consecutive integers, and set T consists 4 11 Mar 2008, 11:31
Set S consists of five consectuve integers, and set T 5 16 Jun 2006, 21:33
Set S consists of 5 consecutive integers. Set T consists of 10 18 Aug 2005, 08:07
Display posts from previous: Sort by