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Set T consists of 19 elements. The average of set T is L. If

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Set T consists of 19 elements. The average of set T is L. If [#permalink]

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New post 24 Jul 2011, 10:29
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Set T consists of 19 elements. The average of set T is L. If a new element is added to the set and the average grows by K, what is the value of the new element?

a) L(1 + K / 5)
b) L * (K/100) - 20L
c) 20L(1+K/100)
d) 20(1+K/100)-19L
e) L*(K/5)-19L

GMATClub Toolkit DS Question 93

Spoiler:
My question: So when a question mentions grows by is that always a percentage? In this case, based on the answer, it seems that K is a percentage. Shouldn't it say grows by K% if its a percentage? Or does the word grows is enough to make the % implicit?

In the answer it calculates the new average as (1 + K/100) L whereas I was trying L + K.

Thanks in advance!
[Reveal] Spoiler: OA
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Re: GMATClub Toolkit DS Question 93 [#permalink]

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New post 24 Jul 2011, 22:15
I'll go with you.

If questions says "Grows by K", I'd take it as grows by K in absolute terms. If questions wants to convey the "K in percentage terms" , it should say so explicitly.

this can not be taken as implicit.
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Re: GMATClub Toolkit DS Question 93 [#permalink]

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On the GMAT, whenever something grows by a percentage, you will find it explicitly mentioned. In this instance, grows by K means growing by a factor of K, not by k%.

Remember that these three things are different:
1. Grows by k: This means literally adding k to the original number. If the original number is x, the result is x+k.
2. Grows by k times: This means the new number is the old number plus k times the number. If the original number is x, the result is x + kx = x (1+k)
3. Grows to k times: This means the new number is simply k times the old number. If the original number is x, the result is kx.
4. Grows by k%: In this case, we simply add k% of the number to itself. If the original number is x, the result is x(1 + k/100)
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Re: Set T consists of 19 elements. The average of set T is L. If [#permalink]

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New post 17 Sep 2013, 11:56
gr8tWo wrote:
Set T consists of 19 elements. The average of set T is L. If a new element is added to the set and the average grows by K, what is the value of the new element?

a) L(1 + K / 5)
b) L * (K/100) - 20L
c) 20L(1+K/100)
d) 20(1+K/100)-19L
e) L*(K/5)-19L

GMATClub Toolkit DS Question 93

Spoiler:
My question: So when a question mentions grows by is that always a percentage? In this case, based on the answer, it seems that K is a percentage. Shouldn't it say grows by K% if its a percentage? Or does the word grows is enough to make the % implicit?

In the answer it calculates the new average as (1 + K/100) L whereas I was trying L + K.

Thanks in advance!


Sol: according to the literal meaning of the question

(L+k)= (19L+X)/20
X= new value

X= L+20K
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Re: Set T consists of 19 elements. The average of set T is L. If [#permalink]

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New post 18 Sep 2013, 22:39
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Here according to the problem description, "the average grows by K" --> which implies that the new average will be "L+k"

Solution :

Let's assume the value of new element to be "a". So converting the word problem into equation,

(19*L + a) / (19 + 1) = L + k ==> after solving the equation we will get a (value of newly added element) = L + 20K


But according to the answer options, problem writer wanted to convey " k% percent rise in average value " .

If we consider this case than resulting equation will be,

(19*L + a) / ( 19+1 ) = L + (K/100)*L ==> 19L + a = 20 [ L + KL/100]

==> a= 20L + KL/5 -19L

==> a= L + KL/5 , which is equivalent to option [A]
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Re: Set T consists of 19 elements. The average of set T is L. If   [#permalink] 18 Sep 2013, 22:39
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