Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Set W is made up of positive numbers. One number is removed, [#permalink]
07 Jul 2006, 07:47

00:00

A

B

C

D

E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct
0% (00:00) wrong based on 0 sessions

Set W is made up of positive numbers. One number is removed, and the remaining numbers comprise set V. Is the mean of the numbers in V equal to the mean of the numbers in W?

(1) All numbers in W are integers.
(2) The mean of the numbers in W is 17.5.

I know it is not (A). I am pretty confident it is not (B). (Just pick 3 numbers for W with average 17.5 and experiment with removing one. There infinite number of possibilities.)

I know it is not (A). I am pretty confident it is not (B). (Just pick 3 numbers for W with average 17.5 and experiment with removing one. There infinite number of possibilities.)

I - insufficient - Ifall no.s are same, then mean can be same.. or if no.s are different, then anything is possible.

II. insufficient - mean is 17.5.. it may be possible to have all no.s as 17.5, which would yield same mean for V/W .. or no.s can be differnet, yielding to dif. mean.

Combining,
we know that no.s are integers and not all integers are same .. So, If we remove one integer from the set, it shd yield a diff. mean

Combining, we know that no.s are integers and not all integers are same .. So, If we remove one integer from the set, it shd yield a diff. mean

Still not convinced this proves it. What if you find a set with all but one integers the same that yields 17.5 as average? If you remove any one number from (assuming there more than 3 numbers in the set) the set the median would not change. Is it true that there would be no combination that can give you mean of 17.5 again? Hard to believe, there are so many numbers out there...

Combining, we know that no.s are integers and not all integers are same .. So, If we remove one integer from the set, it shd yield a diff. mean

Still not convinced this proves it. What if you find a set with all but one integers the same that yields 17.5 as average? If you remove any one number from (assuming there more than 3 numbers in the set) the set the median would not change. Is it true that there would be no combination that can give you mean of 17.5 again? Hard to believe, there are so many numbers out there...

sorry guys. i was rushing to guess B thinking that all numbers in set w are integers. it should be C.

we know from 1 and 2 that w has all integers and the number of integers is even. for ex: 10, 15, 20, 25. the sum is 70 and avg = 17.5. if we take out one integer, the avg of the remaining integers wont be the same. it is only possible with numbers.

I - insufficient - Ifall no.s are same, then mean can be same.. or if no.s are different, then anything is possible.

II. insufficient - mean is 17.5.. it may be possible to have all no.s as 17.5, which would yield same mean for V/W .. or no.s can be differnet, yielding to dif. mean.

Combining, we know that no.s are integers and not all integers are same .. So, If we remove one integer from the set, it shd yield a diff. mean

Aren't you assuming that all the integers are different ?? As I understand, unelss mentioned that all integers are different,we have consider a situation where they could be same..

I´ve done an interview at Accepted.com quite a while ago and if any of you are interested, here is the link . I´m through my preparation of my second...

It has been a good week so far. After the disappointment with my GMAT score, I have started to study again, re-schedule the new test date and talked with...

It’s here. Internship season. The key is on searching and applying for the jobs that you feel confident working on, not doing something out of pressure. Rotman has...

Undoubtedly, Durham is an amazing and beautiful place. Just this morning I took a picture at one of the paths that take you from the parking lot to school. You...