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for me it is C.
Neither statement by itself is sufficient - it is clear.
SUM of elements in W or V is also integer (from statement1).
From statement 2 if the mean is 17.5 then it shows the # of elements in set W is EVEN. Then in order to be equal the mean of the set also must be 17.5 but EVEN-1(1 element is removed ) is ODD , so the # of elements of set V is odd. ODD*17,5=not integer but as the all the elements in both sets are integer sum also must be INTEGER but here not
tharefore MEAN of set V must be integer not 17.5 .