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# Set X has 5 numbers, which average is greater than their

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13 Apr 2005, 14:28
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Set X has 5 numbers, which average is greater than their median. Set Y has 7 numbers, which average is greater than their median also. If the 2 sets have no common number and are combined to a new set, is the average of the new set greater than its median?
1) The average of Y is greater than the average of X
2) The median of Y is greater than the median of X
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13 Apr 2005, 14:52
C

The median of Y and the Mean of Y being greater than those of X already tells us how the data is dispersed
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13 Apr 2005, 22:08
I don't have OA, but guys, please give me your comments. Thanks
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14 Apr 2005, 03:27
DLMD wrote:
I don't have OA, but guys, please give me your comments. Thanks

PLugged in some values and got C.

S1 = { 1,3,5,21,23} ==>> Avg = 10.6 which is greater than 5 the median

S2 = {7,9,11,31,35} ==>> Avg = 186. whihcs again > median whihc is 11

Combining S1 and S2

SCombo = { 1,3,5,7,9,....35} Avg = 14.6

Med = 10

So the answer is C
14 Apr 2005, 03:27
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# Set X has 5 numbers, which average is greater than their

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