dreambeliever wrote:

Set X consists of seven consecutive integers, and set Y consists

of nine consecutive integers. Is the median of the numbers in

set X equal to the median of the numbers in set Y ?

(1) The sum of the numbers in set X is equal to the sum of

the numbers in set Y.

(2) The median of the numbers in set Y is 0.

1- Insufficient

There are 7 consecutive integers in X. Lets say the smallest x. The others will be x+1...x+6

There are 9 consecutive integers in Y. Lets say the smallest y. The others will be y+1...y+8

Sum of X = 7x+21= 7.(x+3)

Sum of Y = 9y+36 =9.(y+4)

if Sum of X = Sum of Y then makes 7(x+3)=9(y+4)..................(1)

median of X = x+3

median of Y = y+4

if median of X = median of Y then 7(x+3) must be equal to 9 (x+3) it is possible in only one case that is x=-3.

So we do not infer from this statement that median of x is equal to median of y.

2) we do not know anything about X

getting them together

we see that y+4= 0, so y = -4

and total of them are 0

and if total of X = 0 and X consists of 7 consequtive integers, X must be -3,..0,..3

So medians are equal

D