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sets31 Q36

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Joined: 20 Mar 2005
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sets31 Q36 [#permalink]  03 Nov 2007, 23:30
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Re: sets31 Q36 [#permalink]  03 Nov 2007, 23:37
You get the equation

10x + 20 y = k (x+y)

Solve by substitution.
I started with 15
I got x = y but Y>x
then 18, y = 4 x => correct

then 30, y = -2 x = > wrong

Balvinder wrote:
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Joined: 01 Nov 2007
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It is D = 18

10x + 20y = kx +ky

For x<y to be true k can take values from 16 to 19.
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