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Seven beads are in a bag: three blue, two red, and two

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Manager
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Seven beads are in a bag: three blue, two red, and two [#permalink] New post 10 Sep 2004, 12:43
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Seven beads are in a bag: three blue, two red, and two green. If three beads are randomly drawn from the bag, what is the probability that they are not all blue?

A. 5/7
B. 23/24
C. 6/7
D. 34/35
E. 8/13
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 [#permalink] New post 10 Sep 2004, 12:53
D. 34/35

They are not all blue - means there could be '1 blue' or 'two blue' or 'all of other color'.

So, we have

(3C1*4C2)/7C3 + (3C2*4C1)/7C3 + 4C3/7C3 = 18/35 + 12/35 + 4/35 = 34/35.

Last edited by venksune on 10 Sep 2004, 13:12, edited 1 time in total.
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 [#permalink] New post 10 Sep 2004, 12:55
Prob of no blue = 1- (prob that all are blue)
= 1- 3C3/7C3 = 34/35............D!!
  [#permalink] 10 Sep 2004, 12:55
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Seven beads are in a bag: three blue, two red, and two

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