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Seven family members are seated around their circular dinner

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VP
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Joined: 13 Jun 2004
Posts: 1128
Location: London, UK
Schools: Tuck'08
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Kudos [?]: 19 [0], given: 0

GMAT Tests User
Seven family members are seated around their circular dinner [#permalink] New post 07 Sep 2004, 16:29
Seven family members are seated around their circular dinner table. If only the only arrangements that are considered distinct are those where family members are seated in different locations relative to each other, then how many distinct arrangements around the table are possible?
(A) 7
(ß) 42
(C) 294
(D) 720
(E) 5040
Manager
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Joined: 05 Sep 2004
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 [#permalink] New post 07 Sep 2004, 18:28
Fix one person and rearrange the others = 6! = 720. D.

Hope that's what the question is asking for.
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GMAT Tests User
 [#permalink] New post 07 Sep 2004, 18:38
Quote:
If only the only arrangements that are considered distinct are those where family members are seated in different locations relative to each other


Above statement is kinda obvious since we are looking for circular arrangements. It is (n-1)! = 6! = 720
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Paul

VP
VP
User avatar
Joined: 13 Jun 2004
Posts: 1128
Location: London, UK
Schools: Tuck'08
Followers: 6

Kudos [?]: 19 [0], given: 0

GMAT Tests User
 [#permalink] New post 07 Sep 2004, 21:52
I agree the question is a little weird...
anyway, you got it right. OA is D.

:done

You both are great GMAT snipers :snipersmile:
  [#permalink] 07 Sep 2004, 21:52
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