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# Seven family members are seated around their circular dinner

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VP
Joined: 13 Jun 2004
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Location: London, UK
Schools: Tuck'08
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Seven family members are seated around their circular dinner [#permalink]

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07 Sep 2004, 16:29
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Seven family members are seated around their circular dinner table. If only the only arrangements that are considered distinct are those where family members are seated in different locations relative to each other, then how many distinct arrangements around the table are possible?
(A) 7
(ÃŸ) 42
(C) 294
(D) 720
(E) 5040
Manager
Joined: 05 Sep 2004
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07 Sep 2004, 18:28
Fix one person and rearrange the others = 6! = 720. D.

Hope that's what the question is asking for.
GMAT Club Legend
Joined: 15 Dec 2003
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07 Sep 2004, 18:38
Quote:
If only the only arrangements that are considered distinct are those where family members are seated in different locations relative to each other

Above statement is kinda obvious since we are looking for circular arrangements. It is (n-1)! = 6! = 720
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Best Regards,

Paul

VP
Joined: 13 Jun 2004
Posts: 1118
Location: London, UK
Schools: Tuck'08
Followers: 7

Kudos [?]: 45 [0], given: 0

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07 Sep 2004, 21:52
I agree the question is a little weird...
anyway, you got it right. OA is D.

You both are great GMAT snipers
07 Sep 2004, 21:52
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