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We have to assume clock and anticlockwise arrangements are the same.
By saying that no two women must seat next to one another means that men and women must alternate in their sitting arrangements.

Let us take the example of 3 men [m1,m2,m3] and 3 women [w1,w2,w3]. That gives us (3-1)= 2 arrangements
[w1 m1 w2 m2 w3 m3 w1]
[w1 m2 w2 m1 w3 m3 w1]

Similarly for 7 men and 7 women we must have (7-1) = 6 combinations.

So i'd go for answer B. Anyway, that is how I would do it should this be an actual GMAT question.

I am unsure of this - after seeing the given answer choices. I dont get any of the answer choices and also way out from any of the ans choices.

Here is my understanding. I will be glad if someone can let me know the logical error I am committing here.

Putting one Man in a fixed position, the remaining men can be arranged in 6! ways.

For each arrangement, there are 7 positions for the women and they can be arranged in 7! ways.

Meaning the total arrangement is 7!*6! = 3628800 ways - only few hundred thousand ways more than the answer choices. Where am I going wrong?

I checked this one venskune, and you are right. This is how even I did it. I have this book which is used for entrance exams ( those competitive exams). and this is how it ihas been done. The OAs are wrong... _________________

Seven men and seven women have to sit around a circular table so that no 2 women are together. In how many ways can that be done?

A. 24 B. 6 C. 4 D. 12 E. 3

I don't have the OA... Please help

The number of arrangements of n distinct objects in a row is given by n!. The number of arrangements of n distinct objects in a circle is given by (n-1)!.

The difference between placement in a row and that in a circle is following: if we shift all object by one position, we will get different arrangement in a row but the same relative arrangement in a circle. So, for the number of circular arrangements of n objects we have: n!/n=(n-1)!

Now, 7 men in a circle can be arranged in (7-1)! ways and if we place 7 women in empty slots between them then no two women will be together. The # of arrangement of these 7 women will be 7! and not 6! because if we shift them by one position we'll get different arrangement because of the neighboring men.

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20 Sep 2013, 01:07

Hello from the GMAT Club BumpBot!

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06 Feb 2014, 09:22

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bumpbot wrote:

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Hi Bumpot, I think what you could do for now is change the answer choices for this question so that we can answer it accordingly since the answer choices given don't make much sense

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07 Feb 2014, 04:50

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jlgdr wrote:

bumpbot wrote:

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Hi Bumpot, I think what you could do for now is change the answer choices for this question so that we can answer it accordingly since the answer choices given don't make much sense

Cheers J

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Re: Seven men and seven women have to sit around a circular [#permalink]

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13 Feb 2015, 06:59

Hello from the GMAT Club BumpBot!

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Seven men and seven women have to sit around a circular [#permalink]

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31 Dec 2015, 18:47

This is a very nice question.

If the men and women were seated in a line not a circle, the answer would be 7!*7!.

However, because they are seated in a circle, where the is no beginning or end, we have to account for repetitions of a pattern that occur when the head to tail arrangement duplicates another pattern but at a different starting point on the circle. For any one pattern, composed of 7 entities, one would expect seven duplicates with different starting points on the circle. Therefore to reach the correct answer one should account for this repetition by dividing 7!*7! by 7 = 7!*6!.

For further clarification consider this:

In a linear arrangement. 1234567 and 2345671 are different patterns. However, in a circular arrangement they are one and the same. So are 3456712, 4567123, 5671234, 6712345 and 7123456.

Because the men and women alternate positionso on the table the pattern advances by two at a time, so even though there are 14 people on the table, there are only 7 positions in each pattern.

Re: Seven men and seven women have to sit around a circular [#permalink]

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03 Jan 2016, 03:26

ComplexVision wrote:

Seven men and seven women have to sit around a circular table so that no 2 women are together. In how many ways can that be done?

A. 5!*6! B. 6!*6! C. 5!*7! D. 6!*7! E. 7!*7!

there are 14 seats on the circular table. for no woman to sit together, the arrangement would be -> MWMWMWM....

so, seat the 7 men at the circular table first in (7-1)! = 6! now the seats for each woman would be between 2 men, hence making it a linear arrangement which can be done in 7!

Re: Seven men and seven women have to sit around a circular [#permalink]

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03 Jan 2016, 06:28

It doesn't matter if you're starting with a man or a woman. If they are alternating in a circular arrangement, two women will never be seated next to each other. My answer was just an explanation of why permutations in a circular arrangement = (n-1)! instead of n!. The group of 14 doesn't literally shift position down the table, but an arbitrary starting point of every set of seven permutations of a sequence, such as the set shown in my answer above, seems to move up and down the circle as you shift between these permutations but the sequence itself remains unchanged.

gmatclubot

Re: Seven men and seven women have to sit around a circular
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03 Jan 2016, 06:28

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