Seven men and seven women have to sit around a circular

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Seven men and seven women have to sit around a circular [#permalink]

23 Oct 2006, 11:04

Seven men and seven women have to sit around a circular table so that no 2 women are together. In how many different ways can this be done?

I think I have posted this before but wanted to post it again as I am not gettign ney idea to solve it. :cry:

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23 Oct 2006, 14:05

Possibility = 7*7 * 6*6 * 5*5 * 4*4 * 3*3 * 2*2 * 1*1 = (7!)^2

We choose:
1 man among 7 and 1 woman among 7,
then, 1 man among 6 and 1 woman among 6
then, 1 man among 5 and 1 woman among 5
... and so on.

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23 Oct 2006, 18:40

I think the answer is 7! * 6!

Explanation -
7 men can be arranged in a circular table in (7 -1)! = 6! ways
Women should sit in the gaps between two men so that no 2 women are together.
There are 7 gaps. So women can arrange themselves in 7! ways.

Possible ways = 7! * 6!

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7!*7! [#permalink]

24 Oct 2006, 17:27

14 places around the table
Wmen can pick 7 plcaes leaving 1 seat so total ways 7!
Men can sit in between the women 7!

7!*7! [#permalink] 24 Oct 2006, 17:27

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Seven men and seven women have to sit around a circular

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Seven men and seven women have to sit around a circular

Seven men and seven women have to sit around a circular

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