**Quote:**

Total ways to seat 7 people = 7! = 5040

Ways that the couple are not together = 7! - (6!*2!) =

5040 - 1440 = 3600

couple not together/total = 3600/5040 = 360/504 = 5/7

Ok, i get a different answer..but i am not real good a probability either..so please check my work

All couples together => total permutations 5! ( 2 couples and 3 kids)

one couple can be seated together in => 2 ! ways

second couple can be seated together in => 2 ! ways

Both the couples can be seated in together => 2! ways

So total = 5! * 2! * 2! * 2! = 6!

i get => 7! - 6! / 7! = 5040-720 / 5040 = 4320 / 5040 = 432 /504

thanks

praetorian