Simple problem but can't get around it.

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Simple problem but can't get around it. [#permalink]

10 May 2011, 08:55

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In My, Xiang sold 15 used cars. For these 15 used cars the range of selling prices was 15,000 and the lowest selling price was 4,500. In June, Xiang sold 10 cars. For these 10 cars the range of selling was 16,000 and the lowest selling price was 6,100. What was the range of selling prices for the 25 used car sold by xiang in May and June?

a)15,600
b)15,750
c)16,820
d)18,100
e)19,200

Thank you

[Reveal] Spoiler: OA

Last edited by patanahi on 10 May 2011, 11:43, edited 1 time in total.

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Re: Simple problem but can't get around it. [#permalink]

10 May 2011, 09:22

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There is a mistake in question stem. I have corrected it below.

For May:
Lowest value: 4500
Range: 15000
Highest value 15000+4500=19,500

For June:
Lowest value: 6100
Range: 16500
Highest value 16500+6100=22,600

For May and June
Lowest Value: 4500
Highest Value: 22,600
Range: 22,600-4500=18,100

OA. D
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Re: Simple problem but can't get around it. [#permalink]

10 May 2011, 11:44

Thank you. I knew it was simple just needed way around :-D

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Re: Simple problem but can't get around it. [#permalink]

10 May 2011, 23:24

for 10 cars - 16000+ 6100 = 22,100
for 15 cars - 15000+ 4500 = 19,500

max = 22,100 min 4500

answer is approx 17600.
Option D is closest.
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Re: Simple problem but can't get around it. [#permalink]

11 May 2011, 04:47

The question is having a typo, please see here :

http://www.manhattangmat.com/forums/vie ... &view=next

I too got 17600 as answer.

Max value in June = 15000 + 4500 = 19500

Max value in June = 16000 + 6100 = 22100

So range = 22100 - 4500 = 17600
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Re: Simple problem but can't get around it. [#permalink] 11 May 2011, 04:47

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Simple problem but can't get around it.

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Simple problem but can't get around it.

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