I'd add another question: how could you multiply the 2 members of the inequality by x^4 if x could be = 0?
I solved this way:
1/x^3-1/x^2 <= 0
since 1/x^2 is always positive, the sign is determined by 1/x-1
so 1/x<=1 => x>=1 (I lost the "x<0" solution)
Where is the mistake?
x can't be = 0....as we have terms in 1/x, which will make 1/x = infinity...in ur soln, everything is correct except when u reverse
1/x <= 1....u can't just say x > = 1....consider when x < 0, that also satisfies 1/x <= 1