neelesh wrote:

Six Married couples are standing in a room. If 4 people are chosen at random, find the probability p for the following scenarios

a) 2 married couples are chosen

b) no married couple is among the 4

c) exactly one married couple is among the 4.

d) at least one married couple is among the 4.

a)2 married couples are chosen

there are 6 married couples so 12 people

prob= 12*10/12c4=1/99

because if u select one person the prob to select its spouse is 1

b) no married couple is among the 4

12*10*8*6/12c4=16/33

c)exactly one married couple is among the 4.

1-((2 married couples are chosen)+(no married couple is among the 4))

1-(1/99+16/33)

d) at least one married couple is among the 4.

1-(no married couple is among the 4)

1-16/33