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small division problem

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GMATD11
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small division problem [#permalink] New post   20 Feb 2011, 11:22
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12,600/12 =1050

when the first two digits or any digit in a number divided evenly we put zero in the quotient.is it true for all or some exception. i think i come across some numbers when divided evenly we don't put zero in between.


My question is y we put zero in quotient when any digit in the number is evenly divided by the denominator.



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Re: small division problem [#permalink] New post   20 Feb 2011, 11:42
GMATD11; I didn't understand your question; but the solution to the problem is as follows:

\(\frac{12600}{12}=1050\). Monthly budget.

For 4 months; 1050*4=4200.
Used; 4580

Exceeded by = 4580-4200=$380

Ans: "A"
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Re: small division problem [#permalink] New post   20 Feb 2011, 11:53
when u divide 12,600/12

as first two digits in a number(12,600) are evenly divisible by denominator 12.

quotient till now we get is 10
right

now my question lies here is y we put zero in quotient.i think while dividing some numbers we don't put zero in quotient when digit in a number is evenly divided by denominator.

Pls comment
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Re: small division problem [#permalink] New post   20 Feb 2011, 12:06
GMATD11 wrote:
when u divide 12,600/12

as first two digits in a number(12,600) are evenly divisible by denominator 12.

quotient till now we get is 10
right

now my question lies here is y we put zero in quotient.i think while dividing some numbers we don't put zero in quotient when digit in a number is evenly divided by denominator.

Pls comment


Right; that's not always true!!!

\(\frac{12600}{12}\).

When we take first 2 digits; i.e. 12 is evenly divided by 12. The remainder is 0. When remainder is 0, we then consider the immediate next digit i.e. 6. The new number becomes 06. 0612.

This is how we divide. But, that's not always true. Consider;

\(\frac{888}{8}\)

Here 8 is evenly divided by 8. We don't need to add 0 in the quotient.

Why; because 8!<8; 8=8.

This is the usual rule for simple division.

Hope I got your question right or may be there is a variance of such rule that I am not aware of!!!



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Re: small division problem [#permalink]
20 Feb 2011, 12:06
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