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# Sole Eqn

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Sole Eqn [#permalink]  27 Mar 2009, 05:26
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Can you explain and solve this one and tell me the roots of x

(x^2-49)(x^2+49)x=0

Thanks
Senior Manager
Joined: 16 Jan 2009
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Concentration: Technology, Marketing
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Re: Sole Eqn [#permalink]  27 Mar 2009, 07:21
I am damn sure that I am missing something here .....still , here is my answer:

either (x^2-49)=0 OR (x^2+49)=0 OR x=0
for (x^2-49)
x= 7 OR x= -7

For (x^2+49)
x= 7i OR x= -7i

x=0

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Re: Sole Eqn [#permalink]  27 Mar 2009, 09:19
While the above post is entirely correct, complex numbers are not tested on the GMAT - all numbers on the GMAT can be assumed to be real numbers. So the equation has three (real) solutions: -7, 0 and 7.
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Re: Sole Eqn [#permalink]  27 Mar 2009, 18:49
I agree complex nos are not in scope, your answer is correct.
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Re: Sole Eqn [#permalink]  06 Sep 2009, 05:40
amolsk11 wrote:
I am damn sure that I am missing something here .....still , here is my answer:

either (x^2-49)=0 OR (x^2+49)=0 OR x=0
for (x^2-49)
x= 7 OR x= -7

For (x^2+49)
x= 7i OR x= -7i

x=0

There is a mistake:
$$x^2+49=0$$
Hence $$x^2=-49$$
This is impossible. This part has no solutions.
H
Re: Sole Eqn   [#permalink] 06 Sep 2009, 05:40
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