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# Solids

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Manager
Joined: 27 Mar 2008
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Solids [#permalink]  19 Apr 2008, 19:04
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A rectangular box is 10 inches wide, 10 " long, and 5" high. What is the greatest possible distance (straight-line), in inches, between any 2 points on the box.
a.15
b. 20
c. 25
d. 10.sqrt(s)
e. 10.sqrt(3)
Director
Joined: 05 Jan 2008
Posts: 707
Followers: 3

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Re: Solids [#permalink]  19 Apr 2008, 19:18
A.15

Draw the diagram and it would be easy to get the calculate the rectangular box.
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VP
Joined: 10 Jun 2007
Posts: 1465
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Re: Solids [#permalink]  19 Apr 2008, 20:20
dishant007 wrote:
A rectangular box is 10 inches wide, 10 " long, and 5" high. What is the greatest possible distance (straight-line), in inches, between any 2 points on the box.
a.15
b. 20
c. 25
d. 10.sqrt(s)
e. 10.sqrt(3)

A.

diagonal = 10sqrt(2)
greatest distance = sqrt((10sqrt(2))^2 + 5^2) = sqrt(225) = 15
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Joined: 28 Dec 2005
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Re: Solids [#permalink]  20 Apr 2008, 03:49
same answer as our other posters. Greatest distance is the diagonal from the bottom corner to the top corner (bottom left to top right, if you want to think about it like that)
Re: Solids   [#permalink] 20 Apr 2008, 03:49
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