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Solution A is 20% salt and Solution B is 80% salt. If you [#permalink]
08 Nov 2005, 18:14

1

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00:00

A

B

C

D

E

Difficulty:

35% (medium)

Question Stats:

73% (08:25) correct
27% (02:40) wrong based on 231 sessions

Solution A is 20% salt and Solution B is 80% salt. If you have 30 ounces of solution A and 60 ounces of solution B, in what ratio could you mix Solution A with Solution B to produce 50 ounces of a 50% salt solution?

Re: Mixture Problem [#permalink]
05 Jul 2011, 06:00

prashantbacchewar wrote:

Solution A is 20% salt and Solution B is 80% salt. If you have 30 ounces of solution A and 60 ounces of solution B, in what ratio could you mix Solution A with Solution B to produce 50 ounces of a 50% salt solution? 6:4 6:14 4:4 4:6 3:7

What is faster way to solve this

I am not good at PS but here is my take on this

6+4/5*y*60 = 1/2 (30 +y*60) Solve: 12+96y=30+60y 36 y = 18 y = 1/2

Re: Mixture Problem [#permalink]
05 Jul 2011, 08:47

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prashantbacchewar wrote:

Solution A is 20% salt and Solution B is 80% salt. If you have 30 ounces of solution A and 60 ounces of solution B, in what ratio could you mix Solution A with Solution B to produce 50 ounces of a 50% salt solution? 6:4 6:14 4:4 4:6 3:7

What is faster way to solve this

Forget the volumes for the time being. You have to mix 20% and 80% solutions to get 50%. This is very straight forward since 50 is int he middle of 20 and 80 so we need both solutions in equal quantities. If this doesn't strike, use w1/w2 = (A2 - Aavg)/(Aavg - A1) w1/w2 = (80 - 50)/(50 - 20) = 1/1 So the volume of the two solutions will be equal. Answer has to be 4:4.

Re: Mixture Problem [#permalink]
06 Jul 2011, 04:19

1

This post received KUDOS

2

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prashantbacchewar wrote:

Solution A is 20% salt and Solution B is 80% salt. If you have 30 ounces of solution A and 60 ounces of solution B, in what ratio could you mix Solution A with Solution B to produce 50 ounces of a 50% salt solution? 6:4 6:14 4:4 4:6 3:7

What is faster way to solve this

Fastest way to solve this Alligations. You can solve any Alligation using this method. Use the diagram, 30:30 = 1:1 hence its C

Re: Solution A is 20% salt and Solution B is 80% salt. If you [#permalink]
16 Dec 2013, 05:57

desiguy wrote:

Solution A is 20% salt and Solution B is 80% salt. If you have 30 ounces of solution A and 60 ounces of solution B, in what ratio could you mix Solution A with Solution B to produce 50 ounces of a 50% salt solution?

Re: Solution A is 20% salt and Solution B is 80% salt. If you [#permalink]
21 Dec 2014, 07:25

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Re: Solution A is 20% salt and Solution B is 80% salt. If you [#permalink]
01 Mar 2015, 03:30

hi karishma why have you considered "percentages" in the scale method...can`t we use the weights of the solutions in the formula as in w1/w2 = (A2 - Aavg)/(Aavg - A1) w1/w2 = (60 - 50)/(50 - 30) = 1/2 please help me with the confusion..

Solution A is 20% salt and Solution B is 80% salt. If you [#permalink]
09 Mar 2015, 15:30

VeritasPrepKarishma wrote:

prashantbacchewar wrote:

Solution A is 20% salt and Solution B is 80% salt. If you have 30 ounces of solution A and 60 ounces of solution B, in what ratio could you mix Solution A with Solution B to produce 50 ounces of a 50% salt solution? 6:4 6:14 4:4 4:6 3:7

What is faster way to solve this

Forget the volumes for the time being. You have to mix 20% and 80% solutions to get 50%. This is very straight forward since 50 is int he middle of 20 and 80 so we need both solutions in equal quantities. If this doesn't strike, use w1/w2 = (A2 - Aavg)/(Aavg - A1) w1/w2 = (80 - 50)/(50 - 20) = 1/1 So the volume of the two solutions will be equal. Answer has to be 4:4.

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