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Solution A is 20% salt and Solution B is 80% salt. If you [#permalink]
08 Nov 2005, 18:14
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Difficulty:
35% (medium)
Question Stats:
73% (06:48) correct
27% (02:35) wrong based on 333 sessions
Solution A is 20% salt and Solution B is 80% salt. If you have 30 ounces of solution A and 60 ounces of solution B, in what ratio could you mix Solution A with Solution B to produce 50 ounces of a 50% salt solution?
Re: Mixture Problem [#permalink]
05 Jul 2011, 06:00
prashantbacchewar wrote:
Solution A is 20% salt and Solution B is 80% salt. If you have 30 ounces of solution A and 60 ounces of solution B, in what ratio could you mix Solution A with Solution B to produce 50 ounces of a 50% salt solution? 6:4 6:14 4:4 4:6 3:7
What is faster way to solve this
I am not good at PS but here is my take on this
6+4/5*y*60 = 1/2 (30 +y*60) Solve: 12+96y=30+60y 36 y = 18 y = 1/2
Re: Mixture Problem [#permalink]
05 Jul 2011, 08:47
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prashantbacchewar wrote:
Solution A is 20% salt and Solution B is 80% salt. If you have 30 ounces of solution A and 60 ounces of solution B, in what ratio could you mix Solution A with Solution B to produce 50 ounces of a 50% salt solution? 6:4 6:14 4:4 4:6 3:7
What is faster way to solve this
Forget the volumes for the time being. You have to mix 20% and 80% solutions to get 50%. This is very straight forward since 50 is int he middle of 20 and 80 so we need both solutions in equal quantities. If this doesn't strike, use w1/w2 = (A2 - Aavg)/(Aavg - A1) w1/w2 = (80 - 50)/(50 - 20) = 1/1 So the volume of the two solutions will be equal. Answer has to be 4:4.
Re: Mixture Problem [#permalink]
06 Jul 2011, 04:19
1
This post received KUDOS
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prashantbacchewar wrote:
Solution A is 20% salt and Solution B is 80% salt. If you have 30 ounces of solution A and 60 ounces of solution B, in what ratio could you mix Solution A with Solution B to produce 50 ounces of a 50% salt solution? 6:4 6:14 4:4 4:6 3:7
What is faster way to solve this
Fastest way to solve this Alligations. You can solve any Alligation using this method. Use the diagram, 30:30 = 1:1 hence its C
Re: Solution A is 20% salt and Solution B is 80% salt. If you [#permalink]
16 Dec 2013, 05:57
desiguy wrote:
Solution A is 20% salt and Solution B is 80% salt. If you have 30 ounces of solution A and 60 ounces of solution B, in what ratio could you mix Solution A with Solution B to produce 50 ounces of a 50% salt solution?
Re: Solution A is 20% salt and Solution B is 80% salt. If you [#permalink]
21 Dec 2014, 07:25
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Re: Solution A is 20% salt and Solution B is 80% salt. If you [#permalink]
01 Mar 2015, 03:30
hi karishma why have you considered "percentages" in the scale method...can`t we use the weights of the solutions in the formula as in w1/w2 = (A2 - Aavg)/(Aavg - A1) w1/w2 = (60 - 50)/(50 - 30) = 1/2 please help me with the confusion..
Solution A is 20% salt and Solution B is 80% salt. If you [#permalink]
09 Mar 2015, 15:30
VeritasPrepKarishma wrote:
prashantbacchewar wrote:
Solution A is 20% salt and Solution B is 80% salt. If you have 30 ounces of solution A and 60 ounces of solution B, in what ratio could you mix Solution A with Solution B to produce 50 ounces of a 50% salt solution? 6:4 6:14 4:4 4:6 3:7
What is faster way to solve this
Forget the volumes for the time being. You have to mix 20% and 80% solutions to get 50%. This is very straight forward since 50 is int he middle of 20 and 80 so we need both solutions in equal quantities. If this doesn't strike, use w1/w2 = (A2 - Aavg)/(Aavg - A1) w1/w2 = (80 - 50)/(50 - 20) = 1/1 So the volume of the two solutions will be equal. Answer has to be 4:4.
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