Ben needs to form a committee of 3 from a group of 8 engineers to study designs. if two of the engineers are too inexperienced to serve together on the committee. how many different committees can ben form?

2 inexperienced engineers

6 engineers

2 conditions

Condition 1 : All 3 from 6 engineers = C(6,3) = 20 ways

Condition 2

Need 1 from 2 inexperienced engineers = C(2,1) = 2

2 from 6 engineers = C(6,2) = 15

Ways = 15*2 = 30

No of different committees = 30+20 = 50.

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