Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 03 May 2015, 20:13

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Solutions x, y and z are mixed at a ratio of 5:7:9

Author Message
TAGS:
Intern
Joined: 29 May 2006
Posts: 6
Location: India
Followers: 0

Kudos [?]: 0 [0], given: 0

Solutions x, y and z are mixed at a ratio of 5:7:9 [#permalink]  29 May 2006, 05:10
Solutions x, y and z are mixed at a ratio of 5:7:9 respectively in order to formulate one batch of 273 gallons of Brand X cleaning fluid. If the supplier of the solutions mixed up the order and supplied 20 gallons less of solution x, 28 gallons more of solution y and 54 gallons less of solution z, how many gallons of Brand X could be made?

a) 231
b) 189
c) 158
d) 156
e) 147

Can someone solve it for me? Thanks.
Director
Joined: 13 Nov 2003
Posts: 793
Location: BULGARIA
Followers: 1

Kudos [?]: 27 [0], given: 0

Hallo raaja,
We need 273 gallons of brand X. Then brand X will contain 273/21=13 gallons of each part multiplied b y the respective ratio. Or x-65, y-91,z-117. When we take into account the confusion of the supplier, we have x 45,y-119, z-63. If we take z=9*7 then we need of each component 7 gallons or x-35,y-49, z-63 and the mixture would be 147 gallons in total
SVP
Joined: 30 Mar 2006
Posts: 1739
Followers: 1

Kudos [?]: 46 [0], given: 0

Its E 147 Gallons of solution

Given 5x+7x+9x = 273 or x=13
Therefore for 273 Gallons we have 65, 91 and 117
But the supplier supplied us with 45, 119 and 63

Now this has to be in the ratio of 5:7:9
hence the final quantities required is 35, 49, 63 = 147
Manager
Joined: 12 Feb 2006
Posts: 115
Followers: 1

Kudos [?]: 26 [0], given: 0

I agree with E.

273/21 = 13 batches.

Based on the info there six less batches because 54/9.

13 - 6 = 7 batches.

7 x 21 = 147
Director
Joined: 09 Oct 2005
Posts: 722
Followers: 3

Kudos [?]: 12 [0], given: 0

jaynayak wrote:
Its E 147 Gallons of solution

Given 5x+7x+9x = 273 or x=13
Therefore for 273 Gallons we have 65, 91 and 117
But the supplier supplied us with 45, 119 and 63

Now this has to be in the ratio of 5:7:9
hence the final quantities required is 35, 49, 63 = 147

Used same approach but it took me more than 3 minut to solve))getting rusty I guess
_________________

IE IMBA 2010

Manager
Joined: 10 May 2006
Posts: 186
Location: USA
Followers: 1

Kudos [?]: 3 [0], given: 0

BG wrote:
Hallo raaja,
We need 273 gallons of brand X. Then brand X will contain 273/21=13 gallons of each part multiplied b y the respective ratio. Or x-65, y-91,z-117. When we take into account the confusion of the supplier, we have x 45,y-119, z-63. If we take z=9*7 then we need of each component 7 gallons or x-35,y-49, z-63 and the mixture would be 147 gallons in total

I got E too, using the same approach. However, I made a couple silly errors along the way, glossing over the line that 28 gallons MORE of solution y was supplied.

Shows I gotta be more careful when reading to avoid silly mistakes.
Intern
Joined: 29 May 2006
Posts: 6
Location: India
Followers: 0

Kudos [?]: 0 [0], given: 0

Thanks for all the responses. The OA is E.
VP
Joined: 29 Dec 2005
Posts: 1349
Followers: 7

Kudos [?]: 30 [0], given: 0

Re: problem on Mixture [#permalink]  31 May 2006, 09:26
raaja wrote:
Solutions x, y and z are mixed at a ratio of 5:7:9 respectively in order to formulate one batch of 273 gallons of Brand X cleaning fluid. If the supplier of the solutions mixed up the order and supplied 20 gallons less of solution x, 28 gallons more of solution y and 54 gallons less of solution z, how many gallons of Brand X could be made?

a) 231
b) 189
c) 158
d) 156
e) 147

= [{(273/21)(9) - 54}/9]21= 147

consider z cuz it is supplied by large reduction. therefore, the qty of z determines the qty of X.

if y were greately reduced, then it would be taken for the calculation.
CEO
Joined: 20 Nov 2005
Posts: 2913
Schools: Completed at SAID BUSINESS SCHOOL, OXFORD - Class of 2008
Followers: 18

Kudos [?]: 121 [0], given: 0

Good questiion.

I came up with E - 147.
_________________

SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

Manager
Joined: 10 May 2006
Posts: 126
Followers: 2

Kudos [?]: 15 [0], given: 0

Here's the approach I followed :-

5a + 7a + 13a = 273 => a=13.

Thus, original quantity: x=65, y=91, z=117

New quantity: x=45, y=119, z=63.

Now, this is the point where you need to figure out, which one should be the limiting quantity. Thankfully, it's pretty easy in this case as z is the one that limits the other two.

Thus, if z=63, one part = 63/9 = 7 litres.
x= 5*7 = 35 litres, and y= 7*7 = 49 litres.

Therefore, total liquid = 63+35+49 = 147 litres.
Similar topics Replies Last post
Similar
Topics:
12 What is the ratio x : y: z ? 7 09 Jan 2014, 20:57
4 Is (2^(y+z))(3^x)(5^y)(7^z) < (90^y)(14^z) 3 28 Sep 2013, 07:59
2 If the ratio x: y:z is 3:5:7, what is the value of z 3 29 Nov 2012, 08:56
8 What is the ratio of x:y:z? 10 27 Nov 2007, 07:17
if x does not equal zero, 2x=5y and 3z=7x what is the ratio 1 23 May 2007, 17:56
Display posts from previous: Sort by