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Solving Quadratic Inequalities: Graphic Approach

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Solving Quadratic Inequalities: Graphic Approach [#permalink] New post 23 Apr 2014, 10:57
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Solving Quadratic Inequalities: Graphic Approach



Say we need to find the ranges of \(x\) for \(x^2-4x+3<0\). \(x^2-4x+3=0\) is the graph of a parabola and it look likes this:
Image

Intersection points are the roots of the equation \(x^2-4x+3=0\), which are \(x_1=1\) and \(x_2=3\). "<" sign means in which range of \(x\) the graph is below x-axis. Answer is \(1<x<3\) (between the roots).

If the sign were ">": \(x^2-4x+3>0\). First find the roots (\(x_1=1\) and \(x_2=3\)). ">" sign means in which range of \(x\) the graph is above x-axis. Answer is \(x<1\) and \(x>3\) (to the left of the smaller root and to the right of the bigger root).


This approach works for any quadratic inequality. For example: \(-x^2-x+12>0\), first rewrite this as \(x^2+x-12<0\) (so that the coefficient of x^2 to be positive. It's possible to solve without rewriting, but easier to master one specific pattern).

\(x^2+x-12<0\). Roots are \(x_1=-4\) and \(x_1=3\) --> below ("<") the x-axis is the range for \(-4<x<3\) (between the roots).

Again if it were \(x^2+x-12>0\), then the answer would be \(x<-4\) and \(x>3\) (to the left of the smaller root and to the right of the bigger root).


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Re: Solving Quadratic Inequalities: Graphic Approach [#permalink] New post 28 May 2014, 03:23
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Re: Solving Quadratic Inequalities: Graphic Approach [#permalink] New post 12 Jul 2015, 10:08
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Re: Solving Quadratic Inequalities: Graphic Approach   [#permalink] 12 Jul 2015, 10:08
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