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Some of the people in Town X are left-handed, some are tall [#permalink]
05 Dec 2009, 09:27

8

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

75% (hard)

Question Stats:

65% (03:47) correct
35% (03:22) wrong based on 155 sessions

Some of the people in Town X are left-handed, some are tall, some are both, and some are neither. In Town Y, three times as many people are left-handed > as are left-handed in Town X, three times as many people are tall as are tall in Town X, three times as many people are both as are both in Town X, but no one is neither. If the total number of people in Town X is four times greater than the total number of people in Town Y, which of the following could be the number of people in Town X who are neither left-handed nor tall?

Re: Some of the people in Town X are left-handed, some are tall [#permalink]
24 Feb 2012, 14:39

3

This post received KUDOS

Expert's post

2

This post was BOOKMARKED

Bullet wrote:

Some of the people in Town X are left-handed, some are tall, some are both, and some are neither. In Town Y, three times as many people are left-handed > as are left-handed in Town X, three times as many people are tall as are tall in Town X, three times as many people are both as are both in Town X, but no one is neither. If the total number of people in Town X is four times greater than the total number of people in Town Y, which of the following could be the number of people in Town X who are neither left-handed nor tall?

I calculated OA and it looks like D but i'm not 100% sure

Yes, correct answer is indeed D.

Given: {X}={Left} + {Tall} - {Both} + {Neither};

{Y} = 3*{Left} + 3*{Tall} - 3*{Both};

Since the total number of people in Town X is four times greater than the total number of people in Town Y, then: {Left} + {Tall} - {Both} + {Neither}=4*(3*{Left} + 3*{Tall} - 3*{Both});

{Neither}=11*({Left} + {Tall} - {Both}), which means that # of people in Town X who are neither left-handed nor tall must be a multiple of 11.

Only answer choice D, is a multiple of 11: 143=11*13.

Re: Some of the people in Town X are left-handed, some are tall [#permalink]
13 Jul 2012, 01:08

I am not fine with the language with this question.. does four times greater right usage.. or should it be four times..does the same meaning is construed.

Re: Some of the people in Town X are left-handed, some are tall [#permalink]
16 Dec 2013, 16:37

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Re: Some of the people in Town X are left-handed, some are tall [#permalink]
01 Mar 2015, 10:57

Hello from the GMAT Club BumpBot!

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Re: Some of the people in Town X are left-handed, some are tall [#permalink]
01 Mar 2015, 17:55

Hi Bunnel,

I have a quick question. The question says "total number of people in Town X is four times greater than the total number of people in Town Y". Wouldn't this translate to X=5Y instead of X=4Y. Sorry if I am missing something.

Re: Some of the people in Town X are left-handed, some are tall [#permalink]
16 Apr 2015, 18:51

Bunuel wrote:

Bullet wrote:

Some of the people in Town X are left-handed, some are tall, some are both, and some are neither. In Town Y, three times as many people are left-handed > as are left-handed in Town X, three times as many people are tall as are tall in Town X, three times as many people are both as are both in Town X, but no one is neither. If the total number of people in Town X is four times greater than the total number of people in Town Y, which of the following could be the number of people in Town X who are neither left-handed nor tall?

I calculated OA and it looks like D but i'm not 100% sure

Yes, correct answer is indeed D.

Given: {X}={Left} + {Tall} - {Both} + {Neither};

{Y} = 3*{Left} + 3*{Tall} - 3*{Both};

Since the total number of people in Town X is four times greater than the total number of people in Town Y, then: {Left} + {Tall} - {Both} + {Neither}=4*(3*{Left} + 3*{Tall} - 3*{Both});

{Neither}=11*({Left} + {Tall} - {Both}), which means that # of people in Town X who are neither left-handed nor tall must be a multiple of 11.

Only answer choice D, is a multiple of 11: 143=11*13.

Answer: D.

I think the highlighted portion actually means: If X is the total population of Town X and Y is the total population of town Y then X = 4Y + Y = 5Y The Question stem states 4 times greater than Y not 4 times as much as Y.

Re: Some of the people in Town X are left-handed, some are tall [#permalink]
16 Apr 2015, 23:44

1

This post received KUDOS

Expert's post

earnit wrote:

Bunuel wrote:

Bullet wrote:

Some of the people in Town X are left-handed, some are tall, some are both, and some are neither. In Town Y, three times as many people are left-handed > as are left-handed in Town X, three times as many people are tall as are tall in Town X, three times as many people are both as are both in Town X, but no one is neither. If the total number of people in Town X is four times greater than the total number of people in Town Y, which of the following could be the number of people in Town X who are neither left-handed nor tall?

I calculated OA and it looks like D but i'm not 100% sure

Yes, correct answer is indeed D.

Given: {X}={Left} + {Tall} - {Both} + {Neither};

{Y} = 3*{Left} + 3*{Tall} - 3*{Both};

Since the total number of people in Town X is four times greater than the total number of people in Town Y, then: {Left} + {Tall} - {Both} + {Neither}=4*(3*{Left} + 3*{Tall} - 3*{Both});

{Neither}=11*({Left} + {Tall} - {Both}), which means that # of people in Town X who are neither left-handed nor tall must be a multiple of 11.

Only answer choice D, is a multiple of 11: 143=11*13.

Answer: D.

I think the highlighted portion actually means: If X is the total population of Town X and Y is the total population of town Y then X = 4Y + Y = 5Y The Question stem states 4 times greater than Y not 4 times as much as Y.

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