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# Some part of 50% solution of acid was replaced with 30%

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Some part of 50% solution of acid was replaced with 30% [#permalink]

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28 Oct 2006, 09:06
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Some part of 50% solution of acid was replaced with 30% solution of acid. As a result 40% solution of acid was obtained.What part of orignal solution of acid was replaced.

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28 Oct 2006, 10:38
I am getting 1/2

Say â€˜Aâ€™ amount 50% solution => A / 2 is the acid amount
X amount is taken out from 50% solution => so X / 2 amount of acid taken out
X amount of 30% acid solution added => so 3X/10 amount of acid added

Resultant solution is 40% acid => acid Ratio 40 / 100 = 2 / 5

(Original acid amount â€“ taken out acid amount + added acid amount ) / Total amount = 2/5
=> (A/2 â€“ X/2 + 3X/10)/A = 2/5
=> X = A/2
28 Oct 2006, 10:38
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