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Some part of the 50% solution of acid was replaced with the

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Some part of the 50% solution of acid was replaced with the [#permalink] New post 03 Oct 2008, 22:17
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Some part of the 50% solution of acid was replaced with the equal amount of 30% solution of acid. As a result, 40% solution of acid was obtained. What part of the original solution was replaced?

* \frac{1}{5}
* \frac{1}{4}
* \frac{1}{2}
* \frac{3}{4}
* \frac{4}{5}
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Re: Math Problem on Solutions [#permalink] New post 03 Oct 2008, 22:27
7-t49897?hilit=made

the answer is (C) - 1/2

:)
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Re: Math Problem on Solutions [#permalink] New post 04 Oct 2008, 01:57
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would someone please give an explanation to the answer for the problem. Thanks
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Re: Math Problem on Solutions [#permalink] New post 04 Oct 2008, 02:00
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ast wrote:
would someone please give an explanation to the answer for the problem. Thanks


In the old solution you had two parts of the 50% solution (out of possible two) - in the new solution the you have only one part out of two - meaning you replaced 50% of the solution or 1/2.

:)
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Re: Math Problem on Solutions   [#permalink] 04 Oct 2008, 02:00
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Some part of the 50% solution of acid was replaced with the

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