Some people subscribe to newpaper A and of these 1/5 of the

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Some people subscribe to newpaper A and of these 1/5 of the [#permalink]

11 Sep 2003, 07:14

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3. Some people subscribe to newpaper A and of these 1/5 of the people
also subscribe to paper B. Some people subscribe to paper B and of
these 1/4 of the people also subscibe to paper A. Ratio of people
who subscribed paper B to that of the total number of people?

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11 Sep 2003, 10:26

B=A/5 => A=5B
A=B/4 => B=4A

A+B = 4A+5B = 4A + 5(4A) = 24A
B=4A

B/(A+B)=4A/24A=1/6

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24 Sep 2003, 11:32

Quote:

A+B = 4A+5B = 4A + 5(4A) = 24A
B=4A

B/(A+B)=4A/24A=1/6

Here I disagree with you.

Why ?

if I change the equation to
A+B = 4A + 5B = 4*5B + 5B = 25B

Hence B/(A+B) = 1/25.
So the solution is not unique.

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24 Sep 2003, 12:39

A/5=B/4

the total number of people A+B-A/5=B+4A/5=2B

B/2B=1/2

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02 Nov 2003, 11:31

i guess..it is easy if you assume some numbers...which is divisible by both 5 and 4 ..say 80 as total number of people..
agree with 1/2.
_________________

shubhangi

[#permalink] 02 Nov 2003, 11:31

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Some people subscribe to newpaper A and of these 1/5 of the

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Some people subscribe to newpaper A and of these 1/5 of the

Some people subscribe to newpaper A and of these 1/5 of the

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GMAT Resources

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MBA Resources