Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

100% (01:01) correct
0% (00:00) wrong based on 1 sessions

Of the 120 people in a room, 3/5 are women. If 2/3 of the people are married, what is the maximum number of women in the room who could be unmarried? a)80 b)72 c)48 d)40 e)32

Q2. 3 friends are playing a game in which each person simultaneously displays one of three hand signs; a clenched fist, an open palm, or two extended fingers. How many different combinations of the signs are possible.?

Q2. 3 friends are playing a game in which each person simultaneously displays one of three hand signs; a clenched fist, an open palm, or two extended fingers. How many different combinations of the signs are possible.?

same signs for friends = 3(HHH, EEE, OOO) 2 same signs and one different sign = 2 * 3 = 6 (HHO, HHE, OOH, OOE, EEH, EEO) 3 different signs = 1 (HEO)

Of the 120 people in a room, 3/5 are women. If 2/3 of the people are married, what is the maximum number of women in the room who could be unmarried? a)80 b)72 c)48 d)40 e)32

Of the 120 people in a room, 3/5 are women. If 2/3 of the people are married, what is the maximum number of women in the room who could be unmarried? a)80 b)72 c)48 d)40 e)32

Q2. 3 friends are playing a game in which each person simultaneously displays one of three hand signs; a clenched fist, an open palm, or two extended fingers. How many different combinations of the signs are possible.?

Q2. 3 friends are playing a game in which each person simultaneously displays one of three hand signs; a clenched fist, an open palm, or two extended fingers. How many different combinations of the signs are possible.?

same signs for friends = 3(HHH, EEE, OOO) 2 same signs and one different sign = 2 * 3 = 6 (HHO, HHE, OOH, OOE, EEH, EEO) 3 different signs = 1 (HEO)

total 10

C

A list lost here.... Would be great if u could help me with this.

3 symbols.... and 3 people to choose.... Shouldn't the total symbols comb = 3x3x3 = 27...! _________________

Cheers! JT........... If u like my post..... payback in Kudos!!

|Do not post questions with OA|Please underline your SC questions while posting|Try posting the explanation along with your answer choice| |For CR refer Powerscore CR Bible|For SC refer Manhattan SC Guide|

Q2. 3 friends are playing a game in which each person simultaneously displays one of three hand signs; a clenched fist, an open palm, or two extended fingers. How many different combinations of the signs are possible.?

same signs for friends = 3(HHH, EEE, OOO) 2 same signs and one different sign = 2 * 3 = 6 (HHO, HHE, OOH, OOE, EEH, EEO) 3 different signs = 1 (HEO)

total 10

C

A list lost here.... Would be great if u could help me with this.

3 symbols.... and 3 people to choose.... Shouldn't the total symbols comb = 3x3x3 = 27...!

Here we are talking about combinations and not permutations ... lets take the case of 3 friends and each choosing differnt symbol.

combinations = 1(no matter what each child picks, they will be picking the same 3 signs in different order) permutation = 3!

Here's the answer that I posted earlier. same signs for friends = 3(HHH, EEE, OOO) 2 same signs and one different sign = 2 * 3 = 6 (HHO, HHE, OOH, OOE, EEH, EEO) 3 different signs = 1 (HEO) total 10

Now take 3 different signs - HEO You can have 6 different types you can select(order matters) - HEO HOE EHO EOH OEH OHE Now if the order doesnt matter - then only 1 combination HEO as the rest of the 5 have the same alphabets but in different order.

Of the 120 people in a room, 3/5 are women. If 2/3 of the people are married, what is the maximum number of women in the room who could be unmarried? a)80 b)72 c)48 d)40 e)32

I´ve done an interview at Accepted.com quite a while ago and if any of you are interested, here is the link . I´m through my preparation of my second...

It’s here. Internship season. The key is on searching and applying for the jobs that you feel confident working on, not doing something out of pressure. Rotman has...