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Someone has yto pay 5 bills, each of which are different

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Someone has yto pay 5 bills, each of which are different [#permalink] New post 09 Aug 2006, 01:10
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Someone has yto pay 5 bills, each of which are different from each other. What is the probability that he will pay the highest bill at first and pay the highest bill at first and pay the least in the end?
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 [#permalink] New post 09 Aug 2006, 05:14
Total Possibilities: 5! = 120

Highest First/Lowest Last: 1*3*2*1*1 = 6

Therefore, probability = 6/120 = 1/20

I agree with AK.
  [#permalink] 09 Aug 2006, 05:14
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Someone has yto pay 5 bills, each of which are different

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