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# Sorry to post so many questions, but for some reason these

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Senior Manager
Joined: 27 Aug 2005
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Sorry to post so many questions, but for some reason these [#permalink]  06 Sep 2005, 19:39
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Sorry to post so many questions, but for some reason these seem like they should be easy but I'm missing something somewhere.

If xy=1, what is the value of 2(x+y)^2 / 2(x-y)^2?

(1) 2
(2) 4
(3) 8
(4) 16
(5) 32

I'm really not seeing this one at all...
Intern
Joined: 04 Sep 2005
Posts: 13
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I don't think anyone has figured it out yet.

Here is an earlier post.

http://www.gmatclub.com/phpbb/viewtopic.php?t=18273

One of my student workers is an EE major. We busted out the TI-89 (or whatever the latest version is) and we couldn't get a correct answer.
SVP
Joined: 03 Jan 2005
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Re: GMATPrep: Yet another PS [#permalink]  07 Sep 2005, 17:31
[2(x+y)^2]/[2(x-y)^2]
=(x+y)^2/(x-y)2
=[(x-y)^2+4xy]/(x-y)^2
=1+4/(x-y)^2
=1+4/(x-1/x)^2

x can be anything. Without knowing the value of x or y, there is no single answer to this problem, unless my reading of the question is not correct. The strangest thing is why there's the two 2s in both the denominator and numerator. Seems like there's a typo somewhere.
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Keep on asking, and it will be given you;
keep on seeking, and you will find;
keep on knocking, and it will be opened to you.

Re: GMATPrep: Yet another PS   [#permalink] 07 Sep 2005, 17:31
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