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Source: GMATPrep On a certain sight-seeing tour, the ratio

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Source: GMATPrep On a certain sight-seeing tour, the ratio [#permalink] New post 21 Sep 2007, 20:33
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Source: GMATPrep

On a certain sight-seeing tour, the ratio of the number women to the number of children was 5 to 2. What was the number of men on the sight-seeing tour?

(1) On the sight-seeing tour, the ratio of the number of children to the number of men was 5:11

(2) The number of women on the sight-seeing tour was less than 30
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Re: DS: Sight-Seeing Tour [#permalink] New post 21 Sep 2007, 23:07
Hang Tuah wrote:
Source: GMATPrep

On a certain sight-seeing tour, the ratio of the number women to the number of children was 5 to 2. What was the number of men on the sight-seeing tour?

(1) On the sight-seeing tour, the ratio of the number of children to the number of men was 5:11

(2) The number of women on the sight-seeing tour was less than 30


Is the answer E. Ima hold off on xplanation til OA. I may have messed up in my notes.
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Re: DS: Sight-Seeing Tour [#permalink] New post 22 Sep 2007, 00:04
Hang Tuah wrote:
Source: GMATPrep

On a certain sight-seeing tour, the ratio of the number women to the number of children was 5 to 2. What was the number of men on the sight-seeing tour?

(1) On the sight-seeing tour, the ratio of the number of children to the number of men was 5:11

(2) The number of women on the sight-seeing tour was less than 30


I pick C.

From the ratios in the stem we can determine that the number of women should be a multiple of 5 and the number of children should be a multiple of 10.

Stat 1: Number of men could be anything as long as C:M = 5:11; Insuff

Stat 2: Doesn't say anything about number of men; Insuff

Stat 1 & 2: Suff
Keeping in mind that for the ratios of W:C:M to work, the number of W should be a multiple of 5 and the number of C should be a multiple of 10, the number of women has to be 25 (since it is restricted by stat 2 to under 30; if it wasn't then I would pick E).

Whats the OA?
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 [#permalink] New post 22 Sep 2007, 00:24
I go for C.
From the stem we know that : W:C = 5:2
We're looking for M

Stat1 : C:M =5:11 => W:C:M = 25:10:22 => INSUFF
Stat2 : W<30> INSUFF

Stat1+Stat2 : W/(all) = 25/57.
Since 57 is a prime number, the number of women MUST be a multiple of 25. hence, the number of women could be 25, 50, 75...
SInce Stat2 says that W<30> SUFF

Answer C
What's the OA ?
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Re: DS: Sight-Seeing Tour [#permalink] New post 22 Sep 2007, 03:31
Hang Tuah wrote:
Source: GMATPrep

On a certain sight-seeing tour, the ratio of the number women to the number of children was 5 to 2. What was the number of men on the sight-seeing tour?

(1) On the sight-seeing tour, the ratio of the number of children to the number of men was 5:11

(2) The number of women on the sight-seeing tour was less than 30


I got C,

1st gives another ratio, so we have two ratios, obviously insuff.
2ns insufficient.

Both,

W/M=5/2------->2W=5C
C/M=5/11------>11C=5M

The key point is to remember that W,C,M must be intengers.

From equation 2W=5C, possible values for W are 25,20,15,10,5
thus possible values for C are 10,8,6,4,2, given equation 11C=5M, from these choices M and C are both intengers only when C=10, thus M=22.
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 [#permalink] New post 22 Sep 2007, 06:29
Another one for C,

25:10:55 is the ratio of women to children and to men, if it is less than 30 than only 25 possible, since there is no 1/2 women (unless she is pregnant:))

Ans: C
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 [#permalink] New post 27 Sep 2007, 07:03
sorry guys for the late answer. My internet has been actingup over the last few days.

OA is C.
  [#permalink] 27 Sep 2007, 07:03
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Source: GMATPrep On a certain sight-seeing tour, the ratio

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