jamifahad wrote:

Three runners A,B and C run a race, with runner A finishing 12m ahead of runner B and 18m ahead of runner C, while runner B finishes 8m ahead of runner C. Each runner travels entire distance at a constant speed. What was the length of the race?

A. 36m

B. 48m

C. 60m

D. 72m

E. 84m

|---------------------------L-------------------|L=Length of the track

|-----------------------------C------B----------|A

|------------------------------------|<--12---->| A finishes 12 m ahead of B

|-----------------------------|<------18------->| A finishes 18 m ahead of C

|-----------------------------|<-6->|---------->| So, B was 6 meters ahead of C when A finished the race ------------1

|----------------------------------------C------|B

|----------------------------------------|<-8-->| B finishes 8 meter ahead of C--------------2

From 1 and 2, we can deduce that

B ran a distance of "L-12" meters taking a lead of 6 meters on C.

L-12->6

1 meter-> 6/(L-12) {:This is the per meter lead by B on C}

For the entire race of L meters, the lead would be

L meters->L*6/(L-12)

And we know the final lead was 8 meters

So,

6L/(L-12)=8

3L/(L-12)=4

3L=4L-48

L=48m

Ans: "B"

_________________

~fluke