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Re: Spokesperson: In the 2006 election of the city mayor, 55% of the voter [#permalink]
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A little arithmetic will do the trick here.
Let total voters=100
Females=55;Males=45
Supported=67;Didnt support=33

Option A.If all males supported,female supporters=67-45=22 not half of 55.Incorrect.

Option B.the above case can prove this point also;males=45;females=22.Incorrect.
C-what if there were only 2 candidates and the other recd.the rest ie 33?

D-given in the stem itself.Correct.

E-nothing about the future can be absolutely true.

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Spokesperson: In the 2006 election of the city mayor, 55% of the voter [#permalink]
bepositive wrote:
Spokesperson: In the 2006 election of the city mayor,55% of the voters were female. All the voters were between ages 18 and 70 and 2/3 of them supported the incumbent mayor. The incumbent mayor won the election with a substantially greater number of votes than any other candidate.

If the statements made by the Spokesperson are true, then which of the following must be true?

a.At least 1/2 of the female voters supported the incumbent mayor.
b.The incumbent mayor received stronger support from the female voters than from the male voters.
c.There were no other candidates in the election who received more than 30% of all the votes.
d.45% of the voters in the election were male and none of them were 75 years old.
e.If the proportion of male and female voters in the city remains the same, the incumbent mayor is also likely to win the next election.



It's best to solve this question by taking some numbers -


Let No of Voters in the age group of 18 -20 Years be 300
Female Voters is 165
Male Voters is 135

2/3rd of the Voters support the incumbent Mayor, so 200 voters supported the mayor and are likely to vote in favor of him. ( Assuming all eligible voters cast their votes)
So, The Mayor didn't get 1/3rd of the total Votes , ie 100 votes and won the election by a substantially greater number of votes than any other candidate.

We can say the Winner got 66.67% of the total votes and the other candidates got 33.33% of the total votes cast.


Among the options presented (D) directly flows from the stimulus ( Highlighted parts of the stimulus )

1. 55% of the voters were female = 45% of the voters were male
2. All the voters were between ages 18 and 70 = All the voters were less than 75 Years age.

Remember for a must be true type question PowerScore CR states -

1. Paraphrase / Restate what has already been presented in the stimulus.
2. Results from a combination of 2 or More statements presented in the stimulus.


Thus correct answer is (D)
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Re: Spokesperson: In the 2006 election of the city mayor, 55% of the voter [#permalink]
55% are women & incumbent got 2/3 (66%) of the total votes.

(A) At least 1/2 of the female voters supported the incumbent mayor. -- Incorrect. We don't know that. What if 45% males and 21% women voted for the incumbent? (21% is less than half of total women voters)

(B) The incumbent mayor received stronger support from the female voters than from the male voters. -- Same as A. Incorrect. Not borne out by the passage

(C) There were no other candidates in the election who received more than 30% of all the votes. -- Incorrect. Other candidate can get 34% votes.

(D) 45% of the voters in the election were male and none of them were 75 years old. -- Correct.

(E) If the proportion of male and female voters in the city remains the same, the incumbent mayor is also likely to win the next election. -- We don't know that. And this is also not borne out by the passage.
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Re: Spokesperson: In the 2006 election of the city mayor, 55% of the voter [#permalink]
Hello from the GMAT Club VerbalBot!

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Re: Spokesperson: In the 2006 election of the city mayor, 55% of the voter [#permalink]
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