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# Algebra

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Senior Manager
Joined: 10 Nov 2010
Posts: 270
Location: India
Concentration: Strategy, Operations
GMAT 1: 520 Q42 V19
GMAT 2: 540 Q44 V21
WE: Information Technology (Computer Software)
Followers: 4

Kudos [?]: 23 [0], given: 22

Algebra [#permalink]  05 Apr 2011, 19:34
00:00

Difficulty:

45% (medium)

Question Stats:

52% (02:36) correct 47% (02:13) wrong based on 21 sessions
\sqrt{3-2x}=\sqrt{2x}+1 then 4x^2 =

A) 1
B) 4
C) 2-2x
D) 4x-2
E) 6x-1

Official Guide 12 Question

 Question: 16 Page: 22 Difficulty: 700

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Video Explanations:
[Reveal] Spoiler: OA

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Manager
Joined: 17 Jan 2011
Posts: 243
Followers: 1

Kudos [?]: 21 [0], given: 4

Re: Algebra [#permalink]  05 Apr 2011, 20:26
=>(3-2x)^1/2=(2x)^1/2+1

Square both sides

=>(3-2x)=(2x)+1+2*(2x)^1/2

=>(2-4x)=2*(2x)^1/2

=>(1-2x)=(2x)^1/2

Square both sides again

1 - 4x + 4x^2 = 2x
4x^2=6x-1
So E.
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Manager
Joined: 17 Jan 2011
Posts: 243
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Kudos [?]: 21 [0], given: 4

Re: Algebra [#permalink]  05 Apr 2011, 20:28
GMATD11 wrote:
16.) \sqrt{3-2x}=\sqrt{2x}+1 then 4x^2 =

a) 1
b) 4
c) 2-2x
d) 4x-2
e) 6x-1

Guys i solved and got 1

but OA is different .

I want to know the reason nd different approach that i need to follow.

Alternately, to verify your ans 4x^2 = 1 means x = 1/2
Substitute the value 1/2 in eq, it doesn't make LHS=RHS
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Joined: 16 Nov 2010
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Re: Algebra [#permalink]  05 Apr 2011, 21:34
root(3-2x) - root(2x) = 1

Squaring both sides :

3 - 2x + 2x - 2 * root(6x - 4x^2) = 1

=> -2 * root(6x - 4x^2) = -2

=> root(6x - 4x^2) = 1

Squaring again :

=> 6x - 4x^2 = 1

=> 4x^2 = 6x - 1

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Joined: 01 Feb 2011
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Kudos [?]: 75 [0], given: 42

Re: Algebra [#permalink]  06 Apr 2011, 05:17
Squaring on both sides we have
2-4x = 2*sqrt(2x)
Squaring on both sides again we have
4x^2 = 6x-1

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Re: Algebra   [#permalink] 06 Apr 2011, 05:17
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