Find all School-related info fast with the new School-Specific MBA Forum

It is currently 01 Jul 2015, 17:19

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

Square A is inscribed in circle X. Square B is inscribed in

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
Current Student
User avatar
Affiliations: UWC
Joined: 09 May 2012
Posts: 399
Location: India
GMAT 1: 620 Q42 V33
GMAT 2: 680 Q44 V38
GPA: 3.43
WE: Engineering (Entertainment and Sports)
Followers: 26

Kudos [?]: 436 [0], given: 100

Reviews Badge
Square A is inscribed in circle X. Square B is inscribed in [#permalink] New post 06 Jun 2012, 02:25
4
This post was
BOOKMARKED
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

84% (02:47) correct 16% (01:49) wrong based on 71 sessions
Square A is inscribed in circle X. Square B is inscribed in circle Y. The perimeter of square B is twice the perimeter of square A. The area of circle Y is equal to k multiplied by the area of circle X. What is the value of k ?

A. 2
B. 3
C. 4
D. 6
E. 8
[Reveal] Spoiler: OA
Manager
Manager
User avatar
Affiliations: Project Management Professional (PMP)
Joined: 30 Jun 2011
Posts: 213
Location: New Delhi, India
Followers: 3

Kudos [?]: 38 [0], given: 12

Re: Square A is inscribed in circle X. Square B is inscribed in [#permalink] New post 06 Jun 2012, 03:23
macjas wrote:
Square A is inscribed in circle X. Square B is inscribed in circle Y. The perimeter of square B is twice the perimeter of square A. The area of circle Y is equal to k multiplied by the area of circle X. What is the value of k ?

A. 2
B. 3
C. 4
D. 6
E. 8


If Peri(sqrB)=2 x Per(SqrA)
=> side(sqrB)= 2 x side(SqrA)
=> diagonal(sqrB)= 2 x daigonal(SqrA)
=> Radius of circle B= 2 x Radius of circle B [ as diagonal of square is daimeter of circle]
=> Area of Circle B = 4 x area of cicle a [As area =pie x (radius)^2]
_________________

Best
Vaibhav

If you found my contribution helpful, please click the +1 Kudos button on the left, Thanks

Current Student
User avatar
Status: Waiting...
Joined: 10 Jan 2012
Posts: 30
Concentration: Strategy, International Business
Schools: Duke '15 (M)
GMAT 1: 750 Q48 V42
Followers: 0

Kudos [?]: 10 [0], given: 5

Re: Square A is inscribed in circle X. Square B is inscribed in [#permalink] New post 07 Jun 2012, 01:50
1
This post was
BOOKMARKED
Let a = side of square A;
Let b = side of square B;

Perimeter of B = 4b
Perimeter of A = 4a

Perimeter of B = 2 * Perimeter of A
4b = 2 * 4a;
b = 2a;

From Pythagoras rule, length of a diagonal equals \sqrt{2} * side of the square:
Diagonal of square A = \(\sqrt{2} * a\)
Diagonal of square B = \(\sqrt{2} * b = \sqrt{2} * 2a = \sqrt{8} * a\)

Radius of circle X = Half of Diagonal of square A, since square A is inscribed in circle X = \(\sqrt{2} * a/2;\)
Radius of circle Y = Half of Diagonal of square B, since square B is inscribed in circle Y =\(\sqrt{8} * a/2;\)

Area of circle X = \(Pi * r^2 = Pi * (\sqrt{2} * a/2)^2 = Pi * a/2;\)
Area of circle Y = \(Pi * r^2 = Pi * (\sqrt{8} * a/2)^2 = Pi * 2a;\)

Area of circle Y = \(k *\)Area of circle X
\(Pi * 2a = k * Pi * a/2\)
\(2 = k * 1/2\)
\(k = 4;\)
_________________

If you found my contribution helpful, please click the +1 Kudos button on the left, Thanks


Last edited by Squish on 08 Jun 2012, 00:56, edited 1 time in total.
Manager
Manager
avatar
Joined: 15 Apr 2012
Posts: 93
Location: Bangladesh
Concentration: Technology, Entrepreneurship
GMAT 1: 460 Q38 V17
GMAT 2: Q V
GPA: 3.56
Followers: 0

Kudos [?]: 17 [0], given: 134

Re: Square A is inscribed in circle X. Square B is inscribed in [#permalink] New post 07 Jun 2012, 19:08
Brotha wrote:
Let a = side of square A;
Let b = side of square B;

Perimeter of B = 2b
Perimeter of A = 2a

Perimeter of B = 2 * Perimeter of A
2b = 2 * 2a;
b = 2a;

From Pythagoras rule, length of a diagonal equals \sqrt{2} * side of the square:
Diagonal of square A = \(\sqrt{2} * a\)
Diagonal of square B = \(\sqrt{2} * b = \sqrt{2} * 2a = \sqrt{8} * a\)

Radius of circle X = Half of Diagonal of square A, since square A is inscribed in circle X = \(\sqrt{2} * a/2;\)
Radius of circle Y = Half of Diagonal of square B, since square B is inscribed in circle Y =\(\sqrt{8} * a/2;\)

Area of circle X = \(Pi * r^2 = Pi * (\sqrt{2} * a/2)^2 = Pi * a/2;\)
Area of circle Y = \(Pi * r^2 = Pi * (\sqrt{8} * a/2)^2 = Pi * 2a;\)

Area of circle Y = \(k *\)Area of circle X
\(Pi * 2a = k * Pi * a/2\)
\(2 = k * 1/2\)
\(k = 4;\)


If one side is a then the perimeter should be 4a, right ?Why u wrote 2a?Can you explain?
Current Student
User avatar
Status: Waiting...
Joined: 10 Jan 2012
Posts: 30
Concentration: Strategy, International Business
Schools: Duke '15 (M)
GMAT 1: 750 Q48 V42
Followers: 0

Kudos [?]: 10 [0], given: 5

Re: Square A is inscribed in circle X. Square B is inscribed in [#permalink] New post 08 Jun 2012, 00:57
Aaack! Sorry - my mistake! Have updated it - it should be 4a.
_________________

If you found my contribution helpful, please click the +1 Kudos button on the left, Thanks

Current Student
avatar
Joined: 08 Jan 2009
Posts: 328
GMAT 1: 770 Q50 V46
Followers: 23

Kudos [?]: 106 [0], given: 7

Re: Square A is inscribed in circle X. Square B is inscribed in [#permalink] New post 08 Jun 2012, 04:58
Circle X
let side of square = 1
radius = \(\sqrt{2}\)
area = \(2*(\sqrt{2})^2\) = \(4\)

Circle y
let side of square = 2
radius = \(\sqrt{8}\)
area = \(2*(\sqrt{8})^2\) = \(16\)

area of y / area of x = k
16 / 4 = 4
Manager
Manager
avatar
Joined: 15 Apr 2012
Posts: 93
Location: Bangladesh
Concentration: Technology, Entrepreneurship
GMAT 1: 460 Q38 V17
GMAT 2: Q V
GPA: 3.56
Followers: 0

Kudos [?]: 17 [0], given: 134

Re: Square A is inscribed in circle X. Square B is inscribed in [#permalink] New post 08 Jun 2012, 06:23
[quote="pike"]Circle X
let side of square = 1
radius = \(\sqrt{2}\)
area = \(2*(\sqrt{2})^2\) = \(4\)

Circle y
let side of square = 2
radius = \(\sqrt{8}\)
area = \(2*(\sqrt{8})^2\) = \(16\)

area of y / area of x = k
16 / 4 = 4[/quote

I want to mention one thing...u said the radius is root 2 for the circle X but actually it's the diagonal of the square not the radius and same for the circle Y..correct me if I am wrong..
GMAT Club Legend
GMAT Club Legend
User avatar
Joined: 09 Sep 2013
Posts: 5349
Followers: 310

Kudos [?]: 60 [0], given: 0

Premium Member
Re: Square A is inscribed in circle X. Square B is inscribed in [#permalink] New post 25 Sep 2014, 12:28
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

GMAT Books | GMAT Club Tests | Best Prices on GMAT Courses | GMAT Mobile App | Math Resources | Verbal Resources

SVP
SVP
User avatar
Status: The Best Or Nothing
Joined: 27 Dec 2012
Posts: 1859
Location: India
Concentration: General Management, Technology
WE: Information Technology (Computer Software)
Followers: 23

Kudos [?]: 960 [0], given: 193

Square A is inscribed in circle X. Square B is inscribed in [#permalink] New post 29 Sep 2014, 01:32
pike wrote:

Circle y
let side of square = 2
radius = \(\sqrt{8}\)
area = \(2*(\sqrt{8})^2\) = \(16\)


area of y / area of x = k
16 / 4 = 4


Though answer is correct, radius / area calculation seems incorrect
_________________

Kindly press "+1 Kudos" to appreciate :)

SVP
SVP
User avatar
Status: The Best Or Nothing
Joined: 27 Dec 2012
Posts: 1859
Location: India
Concentration: General Management, Technology
WE: Information Technology (Computer Software)
Followers: 23

Kudos [?]: 960 [0], given: 193

Re: Square A is inscribed in circle X. Square B is inscribed in [#permalink] New post 29 Sep 2014, 01:34
farukqmul wrote:
I want to mention one thing...u said the radius is root 2 for the circle X but actually it's the diagonal of the square not the radius and same for the circle Y..correct me if I am wrong..


As square is inscribed, "Diagonal Of Square" = "Diameter of Circle"
_________________

Kindly press "+1 Kudos" to appreciate :)

Re: Square A is inscribed in circle X. Square B is inscribed in   [#permalink] 29 Sep 2014, 01:34
    Similar topics Author Replies Last post
Similar
Topics:
6 Experts publish their posts in the topic Circle is inscribed in the square as shown in figure PareshGmat 4 01 Sep 2014, 19:46
5 Experts publish their posts in the topic If a square is inscribed in a circle that, in turn, is inscribed in a maive 6 08 Dec 2010, 19:04
A circle is circumscribed around a square and inscribed in a kevincan 2 19 Sep 2006, 12:46
A circle is circumscribed around a square and inscribed in a kevincan 5 09 Jul 2006, 02:40
Circle O is inscribed within square A. Square B is GMATT73 2 29 Oct 2005, 08:55
Display posts from previous: Sort by

Square A is inscribed in circle X. Square B is inscribed in

  Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.