(1) Given that the area of the square is 9, then each side of the square is 3.
The lengthened sides will be of length 3 + x each, and the diagonal of the obtained rectangle being 5,
we can write \((x+3)^2+3^2=5^2\), from which \((x+3)^2=16\), so \(x = 1\).
(2) Obviously, not sufficient, as was already mentioned by "duriangris" in the previous post.
PhD in Applied Mathematics
Love GMAT Quant questions and running.