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square root doubt

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Joined: 29 Jan 2011
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square root doubt [#permalink] New post 20 Sep 2011, 01:25
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(x^2 )(y^2 )(z^2) = 80

then will xyz be +/- \sqrt{80} ?? or just +\sqrt{80}??
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Re: square root doubt [#permalink] New post 20 Sep 2011, 02:03
siddhans wrote:
(x^2 )(y^2 )(z^2) = 80

then will xyz be +/- \sqrt{80} ?? or just +\sqrt{80}??


(xyz)^2=80

xyz=\pm \sqrt{80}
_________________

~fluke

Re: square root doubt   [#permalink] 20 Sep 2011, 02:03
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