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Find the mean number of employees absent as well as the standard deviation. If absenteeism on Wednesday in May is felt to be normally distributed, what is the probability there would be more than 112 people absent on a Wednesday in May?
A. Mean = 96 B. Standard Deviation = 12.41 or 12
C. Probability of more than 112 people absent on Wednesday in month of May
where: mean = 96 std. dev. = 12 X = 112
Z score computation:
z= X - mean / std.dev
z = 112 - 96 / 12
z = 1.33 = 0.4082
On Z distribution table, the value of 1.33 is 0.4082