devilmirror wrote:

Starting with 1, positive integers are written one after the other. What is the 40,000th digit that will be written?

A. 4

B. 2

C. 1

D. 0

E. 3

1-9 -9 digits total

10-99 -180 digits total ( 2 for each of the 90 two-digit numbers)

100-999 - 2700 digits total (3 for each of the 900 3-digit numbers)

1000-9999 - 36,000 digits total (......)

Clearly, the number containing the 40,000th digit will be a five digit number

Up to 999, we have written 38889 digits

Since 40,000-38,889= 1,111 and 1,111/5 =222 with a remainder of 1,

So, the 40,000th digit is the first digit in 10,222 i.e.

1
A

tedious solution- has anybody got another?