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# Steve gets on the elevator at the 11th floor of a building a

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Manager
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Steve gets on the elevator at the 11th floor of a building a [#permalink]  01 Apr 2006, 21:43
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Question Stats:

61% (02:46) correct 39% (01:53) wrong based on 232 sessions
Steve gets on the elevator at the 11th floor of a building and rides up at a rate of 57 floors per minute. At the same time Joyce gets on an elevator on the 51st floor of the same building and rides down at a rate of 63 floors per minute. If they continue traveling at these rates, at which floor will their paths cross?

A. 19
B. 28
C. 30
D. 32
E. 44
[Reveal] Spoiler: OA

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Last edited by Bunuel on 23 Mar 2014, 05:02, edited 1 time in total.
Renamed the topic, edited the question, added the OA and moved to PS forum.
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Steve travels at a rate of 57 floors/60s~1floor/1s

Joyce travels at a rate of 63 floors/60s~1floor/1s

Between them there are approximatelly 40 floors, so they will both have to travel ~ 20 floors to cross each other.... 20 floors is ~ 20 s

We need to use this formula.... Rate*Time=Distance

Steve: 57/60*20=19

Joyce: 63/60*20=21....

Adding things up we get 30......
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Yeah C

Usuing Speed Formula: Speed = Distance / Time

Distance to be covered = 51-11 = 40

Speed of approach = 57 + 63 floors/min

Time = 40/120 = 1/3

So Steve will cover 57x 1/3 floors in that time = 19

So he will be in 19 + 11 floor = 30th Floor
Manager
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yeap its 30 i kinda figured it out ina different way little later because it was bothering me...

but its pretty much the same
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Re: Rate Problem... Really good question [#permalink]  22 Mar 2014, 12:58
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Re: Steve gets on the elevator at the 11th floor of a building a [#permalink]  23 Mar 2014, 19:58
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Distance between Steve & Joyce = 40 floors

Lets say they meet on x floor

Time required for Joyce to reach x floor = Time required for Steve

So the equation would be

$$\frac{x}{57} = \frac{40-x}{63}$$

x = 19

Start is at 11th floor, so 11 + 19 = 30 = Answer = C
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Re: Steve gets on the elevator at the 11th floor of a building a [#permalink]  08 Aug 2015, 04:04
Hello from the GMAT Club BumpBot!

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Re: Steve gets on the elevator at the 11th floor of a building a   [#permalink] 08 Aug 2015, 04:04
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