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# Stumped on this one ..

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Stumped on this one .. [#permalink]

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23 Jun 2007, 13:38
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Stumped on this one ...
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Senior Manager
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25 Jun 2007, 11:15
1/(Sqrt (X+Y))=Sqrt(X+Y)/(X+Y)

[Sqrt(X)+Sqrt(Y)]/(X+Y) >= Sqrt(X+Y)/(X+Y)

First as the denominator is same u can drop.
Everything depends on the Numerator.to check just take square of both sides (numerator is enough):

X+Y+2*Sqrt(x*y)>= X+Y
then 2*Sqrt(x*y)>=0 because X, Y are Positive.
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25 Jun 2007, 20:26
I am going with 1 and 2 only.

3 is actually equal, and so cannot be greater.
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25 Jun 2007, 23:48
Ref (I)
let x=1 and y = 1
1/sqrt(2)=sqrt(2)/2
Hence it's not (I)
25 Jun 2007, 23:48
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