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Sue's monthly earnings consist of a monthly salary and a 4

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Sue's monthly earnings consist of a monthly salary and a 4 [#permalink] New post 05 Jun 2008, 11:11
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Sue's monthly earnings consist of a monthly salary and a 4 percent commission on the portion of her monthly sales that is in excess of $2,000. If Sue's monthly salary was the same in July as in August, how much greater were her sales in July than in August?

(1) Sue's monthly earnings were $3,620 in July and $3,580 in August.
(2) Sue's monthly salary was $3,500 in July and in August.
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Re: Sue's salary [#permalink] New post 05 Jun 2008, 17:03
Wow, another C trap, 2 days in row.

$40 is 4% of an amount, so Sue sold $1000 more merchandise in July than in August.

A is my answer
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Re: Sue's salary [#permalink] New post 05 Jun 2008, 17:59
yeah i think its A as well

we know from the stem that their montly salaries are the same, so the only difference must be due to the difference in sales ....
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Re: Sue's salary [#permalink] New post 05 Jun 2008, 22:28
I go with A
Let monthly salary = x+0.04(y-2000) where x=monthly salary and y= monthly sales
taking equation (1) 3620=x+0.04(y1-2000) &3580=x+0.04(y2-2000)
{since monthly salary is the same)
above equation can be solved to give y1-y2.........SUFFICIENT

taking (2) monthly salary is same so cant say anything abt sales..........INSUFICIENT

Whts the OA?
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Re: Sue's salary [#permalink] New post 05 Jun 2008, 22:50
kevincan wrote:
Sue's monthly earnings consist of a monthly salary and a 4 percent commission on the portion of her monthly sales that is in excess of $2,000. If Sue's monthly salary was the same in July as in August, how much greater were her sales in July than in August?

(1) Sue's monthly earnings were $3,620 in July and $3,580 in August.
(2) Sue's monthly salary was $3,500 in July and in August.


A.

3620 - 3580 = 40 , 40 =( Total_sale - 2000)* 4/100 total sale was greater than 1000$
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Re: Sue's salary [#permalink] New post 06 Jun 2008, 01:50
For (1), what if Sue sold nothing in July ?
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Re: Sue's salary [#permalink] New post 06 Jun 2008, 03:48
kevincan wrote:
Sue's monthly earnings consist of a monthly salary and a 4 percent commission on the portion of her monthly sales that is in excess of $2,000. If Sue's monthly salary was the same in July as in August, how much greater were her sales in July than in August?

(1) Sue's monthly earnings were $3,620 in July and $3,580 in August.
(2) Sue's monthly salary was $3,500 in July and in August.


IMO A is the answer

pretty good question though coz C seems to be the easier choice here
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Re: Sue's salary [#permalink] New post 06 Jun 2008, 08:23
kevincan wrote:
For (1), what if Sue sold nothing in July ?


If that is the case, then the statement in the stem "Sue's monthly salary was the same in July as in August" is inaccurate, so the question is flawed, and E is then the answer.
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Re: Sue's salary [#permalink] New post 06 Jun 2008, 09:21
Good Question...got me...good practice...Thanks kevincan.
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Re: Sue's salary [#permalink] New post 06 Jun 2008, 09:28
kevincan wrote:
Sue's monthly earnings consist of a monthly salary and a 4 percent commission on the portion of her monthly sales that is in excess of $2,000. If Sue's monthly salary was the same in July as in August, how much greater were her sales in July than in August?

(1) Sue's monthly earnings were $3,620 in July and $3,580 in August.
(2) Sue's monthly salary was $3,500 in July and in August.


X+.04(Y-2000)


1:

X+.04(J-2000)=3620

X+.04(A-2000)=3580

--> 4J/100-80+X=3620 --> 370000=4J+100X -->

J=-25X+92500
A=-25X+91500

J-A = 1000



2: Insuff.


A
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Re: Sue's salary [#permalink] New post 06 Jun 2008, 09:37
Impressive GMATBLACKBELT

GMATBLACKBELT wrote:
kevincan wrote:
Sue's monthly earnings consist of a monthly salary and a 4 percent commission on the portion of her monthly sales that is in excess of $2,000. If Sue's monthly salary was the same in July as in August, how much greater were her sales in July than in August?

(1) Sue's monthly earnings were $3,620 in July and $3,580 in August.
(2) Sue's monthly salary was $3,500 in July and in August.


X+.04(Y-2000)


1:

X+.04(J-2000)=3620

X+.04(A-2000)=3580

--> 4J/100-80+X=3620 --> 370000=4J+100X -->

J=-25X+92500
A=-25X+91500

J-A = 1000



2: Insuff.


A

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Re: Sue's salary [#permalink] New post 06 Jun 2008, 12:12
kevincan wrote:
For (1), what if Sue sold nothing in July ?

I don't think that (1) is sufficient, for we don't know her monthly salary. For all we know, it is $3,580 and she sold nothing in August. Then her commission in July, $40, would have been 4% of x - 2,000, where x is her July sales (i.e. $3,000)
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Re: Sue's salary [#permalink] New post 06 Jun 2008, 12:21
kevincan wrote:
kevincan wrote:
For (1), what if Sue sold nothing in July ?

I don't think that (1) is sufficient, for we don't know her monthly salary. For all we know, it is $3,580 and she sold nothing in August. Then her commission in July, $40, would have been 4% of x - 2,000, where x is her July sales (i.e. $3,000)


That's true, but $40 is 4% of $1000.

No matter how you look at it, you'll find that the difference is $1,000.
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Re: Sue's salary [#permalink] New post 06 Jun 2008, 12:26
Imagine that her salary were $3,580 and she had sold $1,500 in August. What would her income be? And she had sold $3,000?
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Re: Sue's salary [#permalink] New post 06 Jun 2008, 12:32
kevincan wrote:
Imagine that her salary were $3,580 and she had sold $1,500 in August. What would her income be? And she had sold $3,000?


If, in August, her income was $3,580 and she sold $1,500, then her base salary is $3,580 because her sales must be over $2000 in order for her to earn 4% of those sales.

Don't focus on the base salary. Instead, focus on the difference of $40.

You know that she earns the same base salary from month to month, so the difference has to come from the sales commission of 4%. If she earns 4% of some number (x) and that gets her $40 more, then we have the equation of .04x = 40. The answer is $1000. No matter what you make the base salary, the difference in commission is always going to be $40.

HOWEVER....I do see your point. If she sold nothing, she would get the same base salary. Then the next month, in order for her to earn $40 more than her base salary, she has to sell $3,000 ($1,000 more than the 2,000) because x - 2000 * .04 = $40. X here has to be $3,000. The difference would be $3,000, not $1,000.

Good point kevincan, this is not an air-tight question.

The question really should state that she sold at least $2,000 every month. Then sales of $0 would not be possible and we would know that $1,000 had to be the answer and #1 was sufficient, but without that information, it truly is insufficient.

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Re: Sue's salary [#permalink] New post 06 Jun 2008, 12:38
jallenmorris wrote:
kevincan wrote:
Imagine that her salary were $3,580 and she had sold $1,500 in August. What would her income be? And she had sold $3,000?


If, in August, her income was $3,580 and she sold $1,500, then her base salary is $3,580 because her sales must be over $2000 in order for her to earn 4% of those sales. That is right

Don't focus on the base salary. Instead, focus on the difference of $40.

You know that she earns the same base salary from month to month, so the difference has to come from the sales commission of 4%. If she earns 4% of some number (x) and that gets her $40 more, then we have the equation of .04x = 40. The answer is $1000. No matter what you make the base salary, the difference in commission is always going to be $40.


Do you agree that in order to have monthly earnings of $3,620 in July, her sales have had to be $3000 ? Remember that the first $2,000 of sales don't have an impact on her monthly earnings.
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Re: Sue's salary [#permalink] New post 06 Jun 2008, 12:42
jallenmorris wrote:
kevincan wrote:
Imagine that her salary were $3,580 and she had sold $1,500 in August. What would her income be? And she had sold $3,000?


If, in August, her income was $3,580 and she sold $1,500, then her base salary is $3,580 because her sales must be over $2000 in order for her to earn 4% of those sales.

Don't focus on the base salary. Instead, focus on the difference of $40.

You know that she earns the same base salary from month to month, so the difference has to come from the sales commission of 4%. If she earns 4% of some number (x) and that gets her $40 more, then we have the equation of .04x = 40. The answer is $1000. No matter what you make the base salary, the difference in commission is always going to be $40.

HOWEVER....I do see your point. If she sold nothing, she would get the same base salary. Then the next month, in order for her to earn $40 more than her base salary, she has to sell $3,000 ($1,000 more than the 2,000) because x - 2000 * .04 = $40. X here has to be $3,000. The difference would be $3,000, not $1,000.

Good point kevincan, this is not an air-tight question.

The question really should state that she sold at least $2,000 every month. Then sales of $0 would not be possible and we would know that $1,000 had to be the answer and #1 was sufficient, but without that information, it truly is insufficient.


Perhaps the question was testing our ability to consider the possiblilty that her base salary was $3,580. I don't see the question as flawed
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Re: Sue's salary [#permalink] New post 06 Jun 2008, 12:44
Maybe it is flawed, but we're not sure yet because you've not posted the OA.

kevincan wrote:
jallenmorris wrote:
kevincan wrote:
Imagine that her salary were $3,580 and she had sold $1,500 in August. What would her income be? And she had sold $3,000?


If, in August, her income was $3,580 and she sold $1,500, then her base salary is $3,580 because her sales must be over $2000 in order for her to earn 4% of those sales.

Don't focus on the base salary. Instead, focus on the difference of $40.

You know that she earns the same base salary from month to month, so the difference has to come from the sales commission of 4%. If she earns 4% of some number (x) and that gets her $40 more, then we have the equation of .04x = 40. The answer is $1000. No matter what you make the base salary, the difference in commission is always going to be $40.

HOWEVER....I do see your point. If she sold nothing, she would get the same base salary. Then the next month, in order for her to earn $40 more than her base salary, she has to sell $3,000 ($1,000 more than the 2,000) because x - 2000 * .04 = $40. X here has to be $3,000. The difference would be $3,000, not $1,000.

Good point kevincan, this is not an air-tight question.

The question really should state that she sold at least $2,000 every month. Then sales of $0 would not be possible and we would know that $1,000 had to be the answer and #1 was sufficient, but without that information, it truly is insufficient.


Perhaps the question was testing our ability to consider the possiblilty that her base salary was $3,580. I don't see the question as flawed

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Re: Sue's salary [#permalink] New post 07 Jun 2008, 01:47
wow. I also thought the answer was A.
But after reading your posts, i should say, it should be C because:
- problem asks for the difference in sales. - and without giving base salary nor sales for each month, we have to account for so many other possibilities (all positive integers less than 2000)
Great post
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Re: Sue's salary [#permalink] New post 07 Jun 2008, 20:39
There is no need 2 know her salary as its the same 4 all the months, so we can just cancel it out frm the toal. We r intersted in the differewcne in sales ,that we can find out by the equations.
kevincan wrote:
kevincan wrote:
For (1), what if Sue sold nothing in July ?

I don't think that (1) is sufficient, for we don't know her monthly salary. For all we know, it is $3,580 and she sold nothing in August. Then her commission in July, $40, would have been 4% of x - 2,000, where x is her July sales (i.e. $3,000)
Re: Sue's salary   [#permalink] 07 Jun 2008, 20:39
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