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Sum of Consecutive Even Number

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Sum of Consecutive Even Number [#permalink] New post 22 Dec 2005, 17:10
Hi,

This sounds like an easy question but I just want to know if there's a quicker way to solve this:

The sum of 50 even number is 2,550. What is the sum of the even integers from 102-200 inclusive.
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Re: Sum of Consecutive Even Number [#permalink] New post 22 Dec 2005, 17:57
twinkle9600 wrote:
The sum of 50 even number is 2,550. What is the sum of the even integers from 102-200 inclusive.

your first statement should be "the sum of first 50 positive even integers is 2550.

n = (200/2)-(102/2)+1=50
sum = n (F+L)/(2)=50(200+102)/2=7550
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Re: Sum of Consecutive Even Number [#permalink] New post 22 Dec 2005, 23:49
twinkle9600 wrote:
Hi,

This sounds like an easy question but I just want to know if there's a quicker way to solve this:

The sum of 50 even number is 2,550. What is the sum of the even integers from 102-200 inclusive.


The series 102,104,...200 forms an AP.
sn = n/2(a+l) where n is the number of terms in the series, a is the first term, and l is the last term.

Number of terms = 50
a = 102
l = 200
sn = 50/2(102+200) = 7550

Last edited by krisrini on 29 Dec 2005, 00:35, edited 1 time in total.
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Re: Sum of Consecutive Even Number [#permalink] New post 23 Dec 2005, 00:05
HIMALAYA wrote:
twinkle9600 wrote:
The sum of 50 even number is 2,550. What is the sum of the even integers from 102-200 inclusive.

your first statement should be "the sum of first 50 positive even integers is 2550.

n = (200/2)-(102/2)+1=50
sum = n (F+L)/(2)=50(200+102)/2=7550


Agree with HIMALAYA's work.
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 [#permalink] New post 28 Dec 2005, 20:12
I get it now. Thanks for your help
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Re: Sum of Consecutive Even Number [#permalink] New post 29 Dec 2005, 00:35
HIMALAYA wrote:
krisrini wrote:
sn = 50/2(102+300) = 7550


200 or 300?


Thanks himalaya that was a typo. I shall edit my post.
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 [#permalink] New post 09 Jan 2006, 13:17
The first sentence does not seem useful.
  [#permalink] 09 Jan 2006, 13:17
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