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Susan drove an average speed of 30 miles per hour for the [#permalink] New post 02 Nov 2010, 06:56
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Susan drove an average speed of 30 miles per hour for the first 30 miles of a trip & then at a average speed of 60 miles/hr for the remaining 30 miles of the trip if she made no stops during the trip what was susan's avg speed in miles/hr for the entire trip

A. 35
B. 40
C. 45
D. 50
E. 55
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Re: susan drove an average speed [#permalink] New post 02 Nov 2010, 07:04
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anilnandyala wrote:
susan drove an average speed of 30 miles per hour for the first 30 miles of a trip & then at a average speed of 60 miles/hr for the remaining 30 miles of the trip if she made no stops during the trip what was susan's avg speed in miles/hr for the entire trip

a 35
b 40
c 45
d 50
e 55


average \ speed=\frac{total \ distance \ covered}{total \ time};

Total distance covered = 30 + 30 = 60 miles;
Total time = 30/30 + 30/60 = 3/2 hours;

average \ speed=\frac{total \ distance \ covered}{total \ time}=\frac{60}{\frac{3}{2}}=40.

Answer: B.
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Susan drove an average speed of 30 mph for the first 30 min [#permalink] New post 19 Mar 2013, 21:05
Susan drove an average speed of 30 miles per hour for the first 30 miles of a trip and then at an average speed of 60 miles per hour for the remaining 30 miles of the trip. If she made no stops during the trip, what was Susan's average speed, in miles per hour, for the entire trip?

a. 35
b. 40
c. 45
d. 50
e. 55

Last edited by jsphcal on 19 Mar 2013, 22:15, edited 1 time in total.
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Re: Susan drove an average speed of 30 mph for the first 30 min [#permalink] New post 19 Mar 2013, 22:05
Your reasoning is correct. Probably the answer is incorrect unless you have not changed either the question or the answer.
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Re: Susan drove an average speed of 30 mph for the first 30 min [#permalink] New post 19 Mar 2013, 22:51
Avg. speed = total distance / total time

Total distance = 60 miles
Total time = 30 / 30 + 30/60 = 3/2

Avg. speed = 40.

Answer - B
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Re: Susan drove an average speed of 30 mph for the first 30 min [#permalink] New post 20 Mar 2013, 02:09
jsphcal wrote:
Susan drove an average speed of 30 miles per hour for the first 30 miles of a trip and then at an average speed of 60 miles per hour for the remaining 30 miles of the trip. If she made no stops during the trip, what was Susan's average speed, in miles per hour, for the entire trip?

a. 35
b. 40
c. 45
d. 50
e. 55


The Common Formula is Average speed = Total distance / Total time.
However if the distances traveled with two different speeds are the same (as 30 in this case), we can calculate the average speed as per following rule.
ratio of two distinct speeds = 1:2
Difference of two distinct speeds = 60 - 30 = 30
Now divide this difference by the sum of intergers of ratio (i.e. by 1+2 = 3 in this case ) 30/3 = 10
Average speed will be 10 X 1 part away from the lower speed i.e. 30 + 10 X 1 = 40.

The benefit of this method is once practiced enough you can calculate the average speed mentally or with minimal calculation and thereby can save valuable time on the GMAT

Regards,

Abhijit
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Last edited by Narenn on 20 Mar 2013, 04:56, edited 1 time in total.
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Re: Susan drove an average speed of 30 mph for the first 30 min [#permalink] New post 20 Mar 2013, 03:31
jsphcal wrote:
Susan drove an average speed of 30 miles per hour for the first 30 miles of a trip and then at an average speed of 60 miles per hour for the remaining 30 miles of the trip. If she made no stops during the trip, what was Susan's average speed, in miles per hour, for the entire trip?

a. 35
b. 40
c. 45
d. 50
e. 55


Merging similar topics.
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Re: Susan drove an average speed of 30 miles per hour for the [#permalink] New post 25 Mar 2013, 11:40
My approach:

30/30 -> 1h
30/60 -> 0.5h
---------1.5h total and then 60/1.5 -> 40 (1.5 -> 3 -> 4.5 -> 6)
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Re: Susan drove an average speed of 30 miles per hour for the   [#permalink] 25 Mar 2013, 11:40
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