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Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 [#permalink]

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15 Apr 2012, 21:16

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Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 identical chairs in straight line so that Susan is seated always left to Tim. How many such arrangements are possible ?

Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 [#permalink]

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16 Apr 2012, 00:58

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gmihir wrote:

Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 identical chairs in straight line so that Susan is seated always left to Tim. How many such arrangements are possible ?

A. 360 B. 120 C. 80 D. 240 E. 60

Total # of arrangement of 6 people is 6!.

In half of the cases Susan will be seated left to Tim and in half of the cases Susan will be seated right to Tim (why should one seating arrangement have more ways to occur than another?).

So, # of arrangements to satisfy the given condition is 6!/2=360.

Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 [#permalink]

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27 Mar 2014, 12:26

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 [#permalink]

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12 Apr 2014, 01:19

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satsymbol wrote:

Why Can not I use Glue method here? SK together, with 4 others - 5! = 120 ways.

Hi,

When you are using the above method what you are assuming is that they are sitting next to each other always, which is not what the question states. The question only says that S is always sitting left of T, maybe next, maybe away 1 chair ...there is no constraint on that.

----------------------------------- Kudos, if the post helped

Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 [#permalink]

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12 Apr 2014, 19:27

ind23 wrote:

satsymbol wrote:

Why Can not I use Glue method here? SK together, with 4 others - 5! = 120 ways.

Hi,

When you are using the above method what you are assuming is that they are sitting next to each other always, which is not what the question states. The question only says that S is always sitting left of T, maybe next, maybe away 1 chair ...there is no constraint on that.

----------------------------------- Kudos, if the post helped

Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 [#permalink]

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26 Apr 2015, 20:34

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________

Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 [#permalink]

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24 Jun 2015, 03:37

Bunuel wrote:

gmihir wrote:

Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 identical chairs in straight line so that Susan is seated always left to Tim. How many such arrangements are possible ?

A. 360 B. 120 C. 80 D. 240 E. 60

Total # of arrangement of 6 people is 6!.

In half of the cases Susan will be seated left to Tim and in half of the cases Susan will be seated right to Tim (why should one seating arrangement have more ways to occur than another?).

So, # of arrangements to satisfy the given condition is 6!/2=360.

Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 [#permalink]

Show Tags

24 Jun 2015, 21:53

Expert's post

gmihir wrote:

Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 identical chairs in straight line so that Susan is seated always left to Tim. How many such arrangements are possible ?

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