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Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6

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Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 [#permalink]

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Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 identical chairs in straight line so that Susan is seated always left to Tim. How many such arrangements are possible ?

A. 360
B. 120
C. 80
D. 240
E. 60
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New post 15 Apr 2012, 21:57
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Total number of arrangements = 6! = 720

In exactly half, Susan will be to the left of Tim, which gives us 360 arrangements

Option (A)
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Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 [#permalink]

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gmihir wrote:
Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 identical chairs in straight line so that Susan is seated always left to Tim. How many such arrangements are possible ?

A. 360
B. 120
C. 80
D. 240
E. 60


Total # of arrangement of 6 people is 6!.

In half of the cases Susan will be seated left to Tim and in half of the cases Susan will be seated right to Tim (why should one seating arrangement have more ways to occur than another?).

So, # of arrangements to satisfy the given condition is 6!/2=360.

Answer: A.

Similar questions to practice:
in-how-many-different-ways-can-the-letters-a-a-b-91460.html
six-mobsters-have-arrived-at-the-theater-for-the-premiere-of-the-126151.html

Hope it helps.
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Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 [#permalink]

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Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 [#permalink]

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New post 11 Apr 2014, 18:47
Why Can not I use Glue method here?
SK together, with 4 others - 5! = 120 ways.
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Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 [#permalink]

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satsymbol wrote:
Why Can not I use Glue method here?
SK together, with 4 others - 5! = 120 ways.




Hi,

When you are using the above method what you are assuming is that they are sitting next to each other always, which is not what the question states.
The question only says that S is always sitting left of T, maybe next, maybe away 1 chair ...there is no constraint on that.

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Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 [#permalink]

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New post 12 Apr 2014, 18:27
ind23 wrote:
satsymbol wrote:
Why Can not I use Glue method here?
SK together, with 4 others - 5! = 120 ways.




Hi,

When you are using the above method what you are assuming is that they are sitting next to each other always, which is not what the question states.
The question only says that S is always sitting left of T, maybe next, maybe away 1 chair ...there is no constraint on that.

-----------------------------------
Kudos, if the post helped


got it.. where i was failing... thanks.. :)
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Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 [#permalink]

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New post 12 Apr 2014, 20:33
No problem:)
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Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 [#permalink]

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New post 26 Apr 2015, 19:34
Hello from the GMAT Club BumpBot!

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Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 [#permalink]

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New post 24 Jun 2015, 02:37
Bunuel wrote:
gmihir wrote:
Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 identical chairs in straight line so that Susan is seated always left to Tim. How many such arrangements are possible ?

A. 360
B. 120
C. 80
D. 240
E. 60


Total # of arrangement of 6 people is 6!.

In half of the cases Susan will be seated left to Tim and in half of the cases Susan will be seated right to Tim (why should one seating arrangement have more ways to occur than another?).

So, # of arrangements to satisfy the given condition is 6!/2=360.

Answer: A.

Similar questions to practice:
in-how-many-different-ways-can-the-letters-a-a-b-91460.html
six-mobsters-have-arrived-at-the-theater-for-the-premiere-of-the-126151.html

Hope it helps.


Hi Bunuel

Could you confirm my thoughts?

If the question asked that Susan should always sit DIRECTLY left to TIM, then the total # of arrangements would be:

5! = 120 ?

Because you can "glue" Kim and Susan "together". But you still have 6 chairs, how would you account for that?

Further: anyone also understod this part "Susan is seated always left to Tim" in the way that Susan needs to be seated directly left to Tim?

Thanks
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Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 [#permalink]

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New post 24 Jun 2015, 20:53
gmihir wrote:
Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 identical chairs in straight line so that Susan is seated always left to Tim. How many such arrangements are possible ?

A. 360
B. 120
C. 80
D. 240
E. 60


This post discusses the symmetry concept and this question: http://www.veritasprep.com/blog/2011/10 ... s-part-ii/
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Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 [#permalink]

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New post 24 Oct 2016, 09:43
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Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6   [#permalink] 24 Oct 2016, 09:43
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