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Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6

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Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 [#permalink] New post 15 Apr 2012, 20:16
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Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 identical chairs in straight line so that Susan is seated always left to Tim. How many such arrangements are possible ?

A. 360
B. 120
C. 80
D. 240
E. 60
[Reveal] Spoiler: OA
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Re: Permutations [#permalink] New post 15 Apr 2012, 21:57
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Total number of arrangements = 6! = 720

In exactly half, Susan will be to the left of Tim, which gives us 360 arrangements

Option (A)
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Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 [#permalink] New post 15 Apr 2012, 23:58
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gmihir wrote:
Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 identical chairs in straight line so that Susan is seated always left to Tim. How many such arrangements are possible ?

A. 360
B. 120
C. 80
D. 240
E. 60


Total # of arrangement of 6 people is 6!.

In half of the cases Susan will be seated left to Tim and in half of the cases Susan will be seated right to Tim (why should one seating arrangement have more ways to occur than another?).

So, # of arrangements to satisfy the given condition is 6!/2=360.

Answer: A.

Similar questions to practice:
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six-mobsters-have-arrived-at-the-theater-for-the-premiere-of-the-126151.html

Hope it helps.
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Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 [#permalink] New post 27 Mar 2014, 11:26
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Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 [#permalink] New post 11 Apr 2014, 18:47
Why Can not I use Glue method here?
SK together, with 4 others - 5! = 120 ways.
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Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 [#permalink] New post 12 Apr 2014, 00:19
satsymbol wrote:
Why Can not I use Glue method here?
SK together, with 4 others - 5! = 120 ways.




Hi,

When you are using the above method what you are assuming is that they are sitting next to each other always, which is not what the question states.
The question only says that S is always sitting left of T, maybe next, maybe away 1 chair ...there is no constraint on that.

-----------------------------------
Kudos, if the post helped
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Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 [#permalink] New post 12 Apr 2014, 18:27
ind23 wrote:
satsymbol wrote:
Why Can not I use Glue method here?
SK together, with 4 others - 5! = 120 ways.




Hi,

When you are using the above method what you are assuming is that they are sitting next to each other always, which is not what the question states.
The question only says that S is always sitting left of T, maybe next, maybe away 1 chair ...there is no constraint on that.

-----------------------------------
Kudos, if the post helped


got it.. where i was failing... thanks.. :)
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Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 [#permalink] New post 12 Apr 2014, 20:33
No problem:)
Do press +1 Kudos if it helped.

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Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6   [#permalink] 12 Apr 2014, 20:33
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