Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6

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Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 [#permalink]

15 Apr 2012, 21:16

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Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 identical chairs in straight line so that Susan is seated always left to Tim. How many such arrangements are possible ?

A. 360
B. 120
C. 80
D. 240
E. 60

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Kudos [?]: 160 [1] , given: 9

Re: Permutations [#permalink]

15 Apr 2012, 22:57

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Total number of arrangements = 6! = 720

In exactly half, Susan will be to the left of Tim, which gives us 360 arrangements

Option (A)
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Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 [#permalink]

16 Apr 2012, 00:58

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gmihir wrote:

Total # of arrangement of 6 people is 6!.

In half of the cases Susan will be seated left to Tim and in half of the cases Susan will be seated right to Tim (why should one seating arrangement have more ways to occur than another?).

So, # of arrangements to satisfy the given condition is 6!/2=360.

Answer: A.

Similar questions to practice:
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Hope it helps.
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Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 [#permalink] 16 Apr 2012, 00:58

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Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6

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Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6

Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6

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