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t1, t2, t3, t4...tn what is the value of n? 1) Sum of n [#permalink ]
09 Jan 2007, 06:43

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60% (01:54) correct

40% (00:50) wrong

based on 5 sessions
t1, t2, t3, t4...tn what is the value of n?

1) Sum of n terms is 3,124

2) Mean of terms is 4

I got a 47 on the prep and these are the dumb ones I get wrong. How to proceed?

Thanks

Eric

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(C) for me

Stat 1
We could have any value for n.

o If n = 1, then Sum t(n) = 3,124 = t(1)

o If n = 100 as well as t(1) = 3,124 and t(k) = 0 with 1 < k <= n, Sum t(n) = 3,124

INSUFF.

Stat 2
Here again, we could have any value of n and get an averge of 4.

INSUFF.

Both (1) & (2)
The rule : Sum / n = av gives us the answer.

n = Sum / av = 3124 / 4 = 781.

SUFF.

Last edited by

Fig on 09 Jan 2007, 07:50, edited 1 time in total.

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Thanks. Looks awfully easy now. Number sequences are hard for me. Not sure why. The math behind them is pretty easy.
Eric

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Yes

.... Usually, the used operands are + or - and *. So we are never so far in the concept of number sequence for the GMAT.

... Pretty good news

I think it's a question of practice to carck and to feel confortable with these questions

ericttz wrote:

Thanks. Looks awfully easy now. Number sequences are hard for me. Not sure why. The math behind them is pretty easy. Eric

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Fig wrote:

(C) for me

Stat 1 We could have any value for n.

o If n = 1, then Sum t(n) = 3,124 = t(1)

o If n = 100 as well as t(1) = 3,124 and t(k) = 0 with 1 < k <= n, Sum t(n) = 3,124

INSUFF.

Stat 2 Here again, we could have any value of n and get an averge of 4.

INSUFF.

Both (1) & (2) The rule : Sum / n = av gives us the answer.

n = Sum / av = 3124 / 4 = 781.

SUFF.

Hi Fig,

can we assume that it is Arithmetic progression?

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aurobindo wrote:

Fig wrote:

(C) for me

Stat 1 We could have any value for n.

o If n = 1, then Sum t(n) = 3,124 = t(1)

o If n = 100 as well as t(1) = 3,124 and t(k) = 0 with 1 < k <= n, Sum t(n) = 3,124

INSUFF.

Stat 2 Here again, we could have any value of n and get an averge of 4.

INSUFF.

Both (1) & (2) The rule : Sum / n = av gives us the answer.

n = Sum / av = 3124 / 4 = 781.

SUFF.

Hi Fig,

can we assume that it is Arithmetic progression?

No. We are never allowed to assume something that restricts the original problems

. We must remain general if the problem is general

It could be any kind of sequences here

.

o t(n) = t(n-1) + 1

o t(n) = t(n-1)

o t(n) = 2*t(n-1)

o t(n) = 1/t(n-1)

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Fig wrote:

aurobindo wrote:

Fig wrote:

(C) for me

Stat 1 We could have any value for n.

o If n = 1, then Sum t(n) = 3,124 = t(1)

o If n = 100 as well as t(1) = 3,124 and t(k) = 0 with 1 < k <= n, Sum t(n) = 3,124

INSUFF.

Stat 2 Here again, we could have any value of n and get an averge of 4.

INSUFF.

Both (1) & (2) The rule : Sum / n = av gives us the answer.

n = Sum / av = 3124 / 4 = 781.

SUFF.

Hi Fig,

can we assume that it is Arithmetic progression?

No. We are never allowed to assume something that restricts the original problems

. We must remain general if the problem is general

It could be any kind of sequences here

.

o t(n) = t(n-1) + 1

o t(n) = t(n-1)

o t(n) = 2*t(n-1)

o t(n) = 1/t(n-1)

Thanks Fig. Now I understand ur logic

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If the terms of sequance are t1, t2, t3.... tn. What is the value of n? 1. The sum of n terms is 3124 2. The average of n terms is 4

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