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# Taken From MGMAT # 3 A convenience store currently stocks 48

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Taken From MGMAT # 3 A convenience store currently stocks 48 [#permalink]  22 Jan 2008, 01:09
Taken From MGMAT # 3

A convenience store currently stocks 48 bottles of mineral water. The bottles have two sizes of either 20 or 40 ounces each. The average volume per bottle the store currently has in stock is 35 ounces. How many 40 ounce bottles must be sold for the average volume per bottle to be reduced to 25 ounces if no 20 ounce bottles are sold?

(A) 10
(B) 20
(C) 30
(D) 32
(E) 34

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Re: Statistics from MGMAT #3 [#permalink]  22 Jan 2008, 01:34
GGUY wrote:
Taken From MGMAT # 3

A convenience store currently stocks 48 bottles of mineral water. The bottles have two sizes of either 20 or 40 ounces each. The average volume per bottle the store currently has in stock is 35 ounces. How many 40 ounce bottles must be sold for the average volume per bottle to be reduced to 25 ounces if no 20 ounce bottles are sold?

(A) 10
(B) 20
(C) 30
(D) 32
(E) 34

D

20x + 40y = 35*48

20x + 40 (y-t) = 25*(48-t)
20x + 40y -40t = 25*48 - 25t
35*48 -40t = 25*48 -25t
t =32
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Re: Statistics from MGMAT #3 [#permalink]  22 Jan 2008, 12:10
sondenso wrote:
GGUY wrote:
Taken From MGMAT # 3
A convenience store currently stocks 48 bottles of mineral water. The bottles have two sizes of either 20 or 40 ounces each. The average volume per bottle the store currently has in stock is 35 ounces. How many 40 ounce bottles must be sold for the average volume per bottle to be reduced to 25 ounces if no 20 ounce bottles are sold?

(A) 10
(B) 20
(C) 30
(D) 32
(E) 34

D

20x + 40y = 35*48

20x + 40 (y-t) = 25*(48-t)
20x + 40y -40t = 25*48 - 25t
35*48 -40t = 25*48 -25t
t =32
Nice, OA= D.

My approach was to find how many bottles of 40 need to remain in order to have 25 Av:

(1) 12*20+40*t = 25* (t+12)
(2) t=4
(3) we found 12 bt of 20 ounce and 36 of 40 ounce so 36-4=32

any more takers?
Re: Statistics from MGMAT #3   [#permalink] 22 Jan 2008, 12:10
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