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Tanks X and Y contain 500 and 200 gallons of water

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Tanks X and Y contain 500 and 200 gallons of water [#permalink] New post 06 Nov 2006, 05:55
00:00
A
B
C
D
E

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(N/A)

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0% (00:00) correct 0% (00:00) wrong based on 0 sessions
Tanks X and Y contain 500 and 200 gallons of water respectively. Water is being pumped out of tank X at a rate of K gallons per minute and water is being added at M gallons per minute. How much time will elapse before the two tanks contain equal amounts of water?

1) 5/(M+K) hours
2) 6*(M+K) hours
3) 300/(M+K) hours
4) 300/(M-K) hours
5) 60/(M-K) hours

Last edited by uvs_mba on 06 Nov 2006, 22:51, edited 1 time in total.
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[#permalink] New post 06 Nov 2006, 08:36
Here is the equation

500 - K*T = 200 + M*T

T * (M+K) = 300

T = 300/ (M+K)

Answer A

Edited made careless mistake

Questions has answers in hour

so T= 300/(M+K)*60 = 5/M+K

Last edited by Damager on 06 Nov 2006, 08:51, edited 1 time in total.
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Re: PS- Water Tanks [#permalink] New post 06 Nov 2006, 08:48
damager got the ans in mins...
divide that by 60 to arrive in hours..

choice a
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 [#permalink] New post 06 Nov 2006, 09:32
haha! I made the same mistake and then I looked at it, lol, was just curious how many people overlook that. lol! By the way thanks a lot for the answer. Yes the answer is A, you guys are great :-D
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 [#permalink] New post 06 Nov 2006, 20:00
This part of the question "water is being added to M gallons per minute" has typo. Please correct it. Thanks.
  [#permalink] 06 Nov 2006, 20:00
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